Python如何使用for循环实现每行打印指定数量的范围内数字？

我是Python新手，之前看过一些每行打印数字的示例但没搞懂，试了\n也没得到想要的效果。我写了一段代码，计算1到1000之间所有偶数的总和，同时打印这些偶数，但现在所有偶数都显示在同一行里。

现有代码 #

sum=0
sq=""

for i in range (0+2,1000+1,2):
   sum+=i
   if i<1000:
      sq=sq+str(i)+","
    
   else:
      sq=sq+str(i)
print(sq, end="\n")
print("Sum of all even numbers within 1 and 1000 =",sum)

当前输出 #

2,4,6,8,10,12,14,16,18,20,22,24,26,28,30,32,34,36,38,40,42,44,46,48,50,52,54,56,58,60,62,64,66,68,70,72,74,76,78,80,82,84,86,88,90,92,94,96,98,100,102,104,106,108,110,112,114,116,118,120,122,124,126,128,130,132,134,136,138,140,142,144,146,148,150,152,154,156,158,160,162,164,166,168,170,172,174,176,178,180,182,184,186,188,190,192,194,196,198,200,202,204,206,208,210,212,214,216,218,220,222,224,226,228,230,232,234,236,238,240,242,244,246,248,250,252,254,256,258,260,262,264,266,268,270,272,274,276,278,280,282,284,286,288,290,292,294,296,298,300,302,304,306,308,310,312,314,316,318,320,322,324,326,328,330,332,334,336,338,340,342,344,346,348,350,352,354,356,358,360,362,364,366,368,370,372,374,376,378,380,382,384,386,388,390,392,394,396,398,400,402,404,406,408,410,412,414,416,418,420,422,424,426,428,430,432,434,436,438,440,442,444,446,448,450,452,454,456,458,460,462,464,466,468,470,472,474,476,478,480,482,484,486,488,490,492,494,496,498,500,502,504,506,508,510,512,514,516,518,520,522,524,526,528,530,532,534,536,538,540,542,544,546,548,550,552,554,556,558,560,562,564,566,568,570,572,574,576,578,580,582,584,586,588,590,592,594,596,598,600,602,604,606,608,610,612,614,616,618,620,622,624,626,628,630,632,634,636,638,640,642,644,646,648,650,652,654,656,658,660,662,664,666,668,670,672,674,676,678,680,682,684,686,688,690,692,694,696,698,700,702,704,706,708,710,712,714,716,718,720,722,724,726,728,730,732,734,736,738,740,742,744,746,748,750,752,754,756,758,760,762,764,766,768,770,772,774,776,778,780,782,784,786,788,790,792,794,796,798,800,802,804,806,808,810,812,814,816,818,820,822,824,826,828,830,832,834,836,838,840,842,844,846,848,850,852,854,856,858,860,862,864,866,868,870,872,874,876,878,880,882,884,886,888,890,892,894,896,898,900,902,904,906,908,910,912,914,916,918,920,922,924,926,928,930,932,934,936,938,940,942,944,946,948,950,952,954,956,958,960,962,964,966,968,970,972,974,976,978,980,982,984,986,988,990,992,994,996,998,1000
Sum of all even numbers within 1 and 1000 = 250500

期望输出 #

2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30, 32, 34, 36, 38, 40
42, 44, 46, 48, 50, 52, 54, 56, 58, 60, 62, 64, 66, 68, 70, 72, 74, 76, 78, 80
…
922, 924, 926, 928, 930, 932, 934, 936, 938, 940, 942, 944, 946, 948, 950, 952, 954,956, 958, 960
962, 964, 966, 968, 970, 972, 974, 976, 978, 980, 982, 984, 986, 988, 990, 992, 994, 996, 998, 1000
Sum of all even numbers within 1 and 1000 = 250500

可以通过计数器跟踪每行的数字数量，每收集20个偶数就打印一行，同时用列表拼接字符串的方式优化性能：

total_sum = 0
line_count = 0
current_line = []

for i in range(2, 1001, 2):
    total_sum += i
    current_line.append(str(i))
    line_count += 1
    
    # 每20个数字打印一行
    if line_count == 20:
        print(", ".join(current_line))
        current_line = []
        line_count = 0

# 打印剩余的数字（避免最后一行遗漏）
if current_line:
    print(", ".join(current_line))

print(f"Sum of all even numbers within 1 and 1000 = {total_sum}")

关键修改说明 #

1. 变量命名优化：将sum改为total_sum，避免和Python内置函数sum重名
2. 行内数字收集：用current_line列表存储当前行的数字字符串，比直接拼接字符串更高效
3. 换行控制：用line_count计数器跟踪当前行的数字数量，达到20个时打印整行并重置列表和计数器
4. 格式处理：用", ".join()自动生成带空格的逗号分隔格式，无需手动判断最后一个数字

内容的提问来源于stack exchange，提问作者SASORRRRI