Python中循环退出后字典内容丢失的问题求助

在函数askduty_oncall中，多层循环内尝试为team_oncall_dict赋值，但退出循环后字典始终为空，导致后续if not team_oncall_dict判断执行foo()。需解决如何保留循环内的字典内容。

相关代码 #

def askduty_oncall(self, *args):
    session = APISession(PD_API_KEY, default_from=PD_USER_EMAIL)
    total = 1 # true or false
    limit = 40
    teamteamnm = "Team Test Team"
    team_esp_name = "Team Test Escalation Policy"  # 修正中文引号为英文
    teamteamid = ""
    teamesplcyid = ""
    team_oncall_dict = {}

    if args:
        offset = args[0]
        total_teams = args[1]
        
        if offset <= total_teams:
            print("\nfunc with args with new offset {} called\n".format(offset))
            teams = session.get('/teams?limit={0}&total={1}&offset={2}'.format(limit,total,offset))
        else:
            print("Reached max teams, no more team records to pull")
            return
    else:
        print("\nFunc with no args called, hence pull first set of {} teams as defined by limit var\n".format(limit))
        teams = session.get('/teams?limit={0}&total={1}'.format(limit,total))
    
    if not teams.ok:
        return
    else:          
        tj = teams.json()
        tjd = tj['teams']
        for adict in tjd:
            if not adict['name'] == teamteamnm:
                continue
            elif adict['name'] == teamteamnm:
                teamteamid = adict['id']
                print("\nFound team..\nFetched",adict['name'], "id: {0}".format(teamteamid))
                print("Pull escalation policy for team '{}':'{}'".format(teamteamnm,teamteamid))
                esclp = session.get('/escalation_policies?total={0}&team_ids%5B%5D={1}'.format(total,teamteamid))
                if not esclp.ok:
                    print("Pulling Escalation polices for team '{}' failed".format(teamteamnm))
                    return
                else:
                    ep = esclp.json()
                    epj = esclp.json()['escalation_policies']
                    if not epj:
                        print("Escalation polices for team '{}' not defined".format(teamteamnm))
                        return
                    else:
                        for adict2 in epj:
                            if not adict2['summary'] == team_esp_name:
                                continue
                            else:
                                print("***************FOUND FOUND********************")
                                teamesplcyid = adict2['id']
                                print("\nFetched {} id: {}\n".format(team_esp_name, teamesplcyid))
                                oncalls = session.get('/oncalls?total={0}&escalation_policy_ids%5B%5D={1}'.format(total,teamesplcyid))
                                if not oncalls.ok:
                                    print("issue with oncalls")  # 修正中文引号为英文
                                    return
                                else:
                                    ocj = oncalls.json()['oncalls']
                                    for adict3 in ocj:
                                        print("\n")
                                        print(adict3['escalation_level'])
                                        if i['escalation_level'] == 1:  # 此处变量名错误
                                            print(adict3['schedule']['summary'], adict3['user']['summary'])
                                            team_oncall_dict[adict3['schedule']['summary']] = adict3['user']['summary']
                                            print(team_oncall_dict)
                                            return team_oncall_dict  # 过早return

    if not team_oncall_dict:  # 需确保缩进属于函数内部
        foo()

执行输出 #

foo stuff

示例数据 #

[
    {'escalation_policy': {'id': 'P8RKTEE', 'type': 'escalation_policy_reference', 'summary': 'Team Escalation Policy'}, 'escalation_level': 3, 'schedule': None, 'user': {'id': 'PX8XYFT', 'type': 'user_reference', 'summary': 'M1'}, 'start': None, 'end': None}, 
    {'escalation_policy': {'id': 'P8RKTEE', 'type': 'escalation_policy_reference', 'summary': 'Team Escalation Policy'}, 'escalation_level': 1, 'schedule': None, 'user': {'id': 'PKXXVJI', 'type': 'user_reference', 'summary': 'R1'}, 'start': None, 'end': None}, 
    {'escalation_policy': {'id': 'P8RKTEE', 'type': 'escalation_policy_reference', 'summary': 'Team'}, 'escalation_level': 2, 'schedule': None, 'user': {'id': 'PN8F9PC', 'type': 'user_reference','summary': 'T1'}, 'start': None, 'end': None}
]

问题分析与修复方案 #

1. 变量名错误导致赋值逻辑未触发 #

内层循环中使用未定义的变量i判断escalation_level，会直接抛出NameError，导致代码根本无法执行到字典赋值步骤。需将i替换为当前循环变量adict3。

2. 过早的return终止函数 #

在字典赋值后立即执行return team_oncall_dict，会直接终止函数，且该return缩进在if判断内部，导致仅找到第一个符合条件的条目就退出，后续循环无法执行。若函数为递归调用，返回值未被外层正确接收时，team_oncall_dict仍为空。需移除该过早的return，或调整到所有循环完成后统一返回。

3. 空指针风险导致赋值失败 #

示例数据中schedule字段为None，直接访问adict3['schedule']['summary']会抛出AttributeError，需先判断schedule不为None再赋值。

4. 语法错误（中文引号） #

代码中多处使用中文引号（如team_esp_name = “Team Test Escalation Policy"），属于语法错误，需替换为英文引号。

5. 缩进错误导致判断逻辑失效 #

末尾的if not team_oncall_dict缩进错误，需确保其属于函数内部的代码块，否则无法正确判断字典状态。

修复后的关键代码片段 #

# 内层循环部分修改
for adict3 in ocj:
    print("\n")
    print(adict3['escalation_level'])
    # 修正变量名+空值判断
    if adict3['escalation_level'] == 1 and adict3['schedule'] is not None:
        print(adict3['schedule']['summary'], adict3['user']['summary'])
        team_oncall_dict[adict3['schedule']['summary']] = adict3['user']['summary']
        print(team_oncall_dict)

# 移除过早的return，在函数末尾统一处理返回或判断
if not team_oncall_dict:
    foo()
# 可选：若需要返回字典，在函数末尾添加
# return team_oncall_dict

内容的提问来源于stack exchange，提问作者AhmFM