如何修改Bash磁盘检查脚本，遍历完所有磁盘后再退出

原脚本的问题是遇到第一个使用率≥90%的分区就直接退出，导致无法报告其他同样需要告警的分区。下面是修改后的脚本，会遍历所有分区、输出所有符合条件的告警信息后，再判断是否需要退出：

#!/bin/bash
LOGFILE="disk_usage.log"
exit_code=0

# 遍历所有磁盘分区，提取使用率和分区路径
df -H | awk 'NR>1 {gsub("%", "", $5); print $5, $1}' | while read -r op partition; do
    if [ "$op" -ge 90 ]; then
        warning_msg=">> ### WARNING! Running out of space on \"$partition ($op%)\" on $(hostname) as on $(date)"
        exit_msg=">> There is not enough left storage in the disk to perform the upgrade, exiting..."
        echo "$warning_msg" >> "$LOGFILE"
        echo -e "$warning_msg"
        echo "$exit_msg" >> "$LOGFILE"
        echo -e "$exit_msg"
        exit_code=1  # 标记存在严重告警，后续统一退出
    elif [ "$op" -ge 85 ]; then
        warning_msg=">> ### WARNING! Running out of space on \"$partition ($op%)\" on $(hostname) as on $(date)"
        advice_msg=">> There is enough left storage in the disk to perform the upgrade, but it is recommended to first increase the size of the disk $partition"
        echo "$warning_msg" >> "$LOGFILE"
        echo -e "$warning_msg"
        echo "$advice_msg" >> "$LOGFILE"
        echo -e "$advice_msg"
    fi
done

# 遍历完成后根据状态决定是否退出
if [ "$exit_code" -eq 1 ]; then
    exit 1
else
    echo -e ">> There is enough left storage in the disk to continue with the upgrade, OK"
fi

关键修改说明： #

• 新增exit_code状态变量，初始为0，检测到≥90%使用率的分区时将其设为1，不立即终止脚本，继续遍历剩余分区
• 优化分区信息提取逻辑：用awk一次性完成去百分号、提取使用率和分区路径操作，减少不必要的管道和子进程调用
• 修复原脚本中的语法错误：将"There enough"修正为"There is enough"
• 把重复的告警文本存入变量，减少代码冗余
• 显式定义日志文件路径，提升脚本可读性

内容的提问来源于stack exchange，提问作者GBT55