Python自定义throw函数无返回值问题求助

Hey there! Let's get that dice-throwing function working so you can finish building your drinking game with friends—sounds like a fun project! 😊

First, let's walk through the issues in your code:

• You forgot to import the random module: Python has no idea what random.randint() is unless you tell it to load the random module first. That's a quick fix.
• You're passing an argument to a function that doesn't accept any: Your throw() function is defined without parameters, but you're calling it as throw(List)—that'll trigger a TypeError immediately.
• The loop logic is off: Your while loop condition was causing the function to generate more than 6 dice rolls (it would make 7, actually!). The way you were tracking iterations with i plus checking the list length was creating a mismatch.

Here's a clean, fixed version of your code using a Pythonic list comprehension (it's shorter and easier to read):

import random

def throw():
    # We want 6 dice rolls, so generate a list of 6 random integers between 1-6
    return [random.randint(1, 6) for _ in range(6)]

# Call the function (no arguments needed!) and print the result
print(throw())

If you'd rather stick with a while loop approach (maybe you're practicing loops specifically), here's the corrected loop version:

import random

def throw():
    dice_count = 6
    roll_list = []
    # Keep adding rolls until we have exactly 6
    while len(roll_list) < dice_count:
        roll_list.append(random.randint(1, 6))
    return roll_list

print(throw())

A quick note: I renamed your variable List to roll_list because using capitalized names like that can clash with Python's built-in types (like list()) and it's not standard practice—small things that make your code easier to maintain later!

内容的提问来源于stack exchange，提问作者Bram van de Poll