Python打印字符串列表时如何去除末尾多余的逗号？

问题代码 #

houses = ['C', 'D', 'H', 'S']
ranks = ['A','2','3','4','5','6','7','8','9','10','J','Q','K']
deck = []

for house in houses:
    for rank in ranks:
        deck.append(f"{rank}-{house}")

for i in range(13):
    print(deck[i], end=",")

期望输出 #

A-C,2-C,3-C,4-C,5-C,6-C,7-C,8-C,9-C,10-C,J-C,Q-C,K-C

实际问题 #

运行上述代码后，输出末尾会多一个不必要的逗号：

A-C,2-C,3-C,4-C,5-C,6-C,7-C,8-C,9-C,10-C,J-C,Q-C,K-C,

解决方法 #

方法1：用str.join()拼接后打印

这是最简洁的方式，直接将目标元素用逗号连接成单个字符串再输出，不会产生末尾多余符号：

houses = ['C', 'D', 'H', 'S']
ranks = ['A','2','3','4','5','6','7','8','9','10','J','Q','K']
deck = []

for house in houses:
    for rank in ranks:
        deck.append(f"{rank}-{house}")

# 取前13个元素，用逗号连接后打印
print(','.join(deck[:13]))

方法2：循环内判断是否为最后一个元素

通过索引判断当前元素是不是最后一个，仅在非末尾元素后添加逗号：

houses = ['C', 'D', 'H', 'S']
ranks = ['A','2','3','4','5','6','7','8','9','10','J','Q','K']
deck = []

for house in houses:
    for rank in ranks:
        deck.append(f"{rank}-{house}")

for i in range(13):
    if i == 12:  # range(13)的最后一个索引是12
        print(deck[i], end="")
    else:
        print(deck[i], end=",")

方法3：利用print()的sep参数

将目标元素解包后传入print()，用sep指定分隔符，天然不会在末尾生成多余符号：

houses = ['C', 'D', 'H', 'S']
ranks = ['A','2','3','4','5','6','7','8','9','10','J','Q','K']
deck = []

for house in houses:
    for rank in ranks:
        deck.append(f"{rank}-{house}")

# 解包前13个元素，用逗号分隔输出
print(*deck[:13], sep=",")

内容的提问来源于stack exchange，提问作者mama b