从两张表获取含最大日期条件的数据及SQL去重求助
解决从两张表中获取最大日期条件数据时的重复记录问题
需求与表结构
需求
获取Subject.name = 'Subject 1'对应的Days记录中,每个name分组下dateTo最大的那条数据。
表结构
- Subject表:
{id = 1, name = 'Subject 1', status = true}, {id = 2, name = 'Subject 2', status = true}, {id = 3, name = 'Subject 3', status = true}
- Days表:
{id = 1, idSubject = 1, name = 'test1', dateFrom = '2022-10-01', dateTo = '2022-10-10'}, {id = 2, idSubject = 1, name = 'test1', dateFrom = '2022-10-02', dateTo = '2022-12-01'}, {id = 3, idSubject = 1, name = 'test2', dateFrom = '2022-01-01', dateTo = '2022-05-10'}, {id = 4, idSubject = 1, name = 'test90', dateFrom = '2022-01-05', dateTo = '2022-12-06'}, {id = 5, idSubject = 2, name = 'ex1', dateFrom = '2022-10-01', dateTo = '2025-01-05'}
期望结果
{id = 2, idSubject = 1, name = 'test1', dateFrom = '2022-10-02', dateTo = '2022-12-01'}, {id = 4, idSubject = 1, name = 'test90', dateFrom = '2022-01-05', dateTo = '2022-12-06'}
原SQL问题分析
你写的SQL子查询中,group by id, date_from, date_to完全失去了分组意义——因为id是Days表的唯一主键,每一行的id都不同,所以这个分组会把每一条Days记录单独作为一组,max(date_to)和max(date_from)就是该行自身的日期值。最终子查询返回所有Days记录,和Subject表join后自然会返回所有关联的记录,而非你期望的筛选后结果。
解决方案
这里提供两种常用的解决方法:
方法1:使用窗口函数(推荐)
利用ROW_NUMBER()窗口函数,按idSubject和name分组,对dateTo降序排序,取每组的第一条记录:
SELECT s.id AS subject_id, d.id, d.idSubject, s.name AS subject_name, d.name, d.dateFrom, d.dateTo FROM Subject s JOIN ( SELECT *, ROW_NUMBER() OVER (PARTITION BY idSubject, name ORDER BY dateTo DESC) AS rn FROM Days ) d ON s.id = d.idSubject WHERE s.name = 'Subject 1' AND d.rn = 1 ORDER BY d.dateTo DESC;
方法2:先分组取最大日期再关联
先查询每个idSubject+name组合对应的最大dateTo,再关联回Days表获取完整记录:
SELECT s.id AS subject_id, d.id, d.idSubject, s.name AS subject_name, d.name, d.dateFrom, d.dateTo FROM Subject s JOIN Days d ON s.id = d.idSubject JOIN ( SELECT idSubject, name, MAX(dateTo) AS max_dateTo FROM Days GROUP BY idSubject, name ) max_d ON d.idSubject = max_d.idSubject AND d.name = max_d.name AND d.dateTo = max_d.max_dateTo WHERE s.name = 'Subject 1' ORDER BY d.dateTo DESC;
这两种方法都能准确筛选出每个name分组下dateTo最大的记录,避免重复。
内容的提问来源于stack exchange,提问作者TommySd
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