MacOS下VSCode运行Python二次方程代码报错求助

在MacOS的VSCode里，除了print("Hello, World")，运行其他Python代码都会弹出以下错误：

Traceback (most recent call last):
  File "/usr/local/Cellar/python@3.10/3.10.8/Frameworks/Python.framework/Versions/3.10/lib/python3.10/runpy.py", line 196, in _run_module_as_main
    return _run_code(code, main_globals, None,
  File "/usr/local/Cellar/python@3.10/3.10.8/Frameworks/Python.framework/Versions/3.10/lib/python3.10/runpy.py", line 86, in _run_code
    exec(code, run_globals)
  File "/Users/juliuseners/.vscode/extensions/ms-python.python-2022.16.1/pythonFiles/lib/python/debugpy/adapter/../../debugpy/launcher/../../debugpy/__main__.py", line 39, in <module>
    cli.main()
  File "/Users/juliuseners/.vscode/extensions/ms-python.python-2022.16.1/pythonFiles/lib/python/debugpy/adapter/../../debugpy/launcher/../../debugpy/../debugpy/server/cli.py", line 430, in main
    run()
  File "/Users/juliuseners/.vscode/extensions/ms-python.python-2022.16.1/pythonFiles/lib/python/debugpy/adapter/../../debugpy/launcher/../../debugpy/../debugpy/server/cli.py", line 284, in run_file
    runpy.run_path(target, run_name="__main__")
  File "/Users/juliuseners/.vscode/extensions/ms-python.python-2022.16.1/pythonFiles/lib/python/debugpy/_vendored/pydevd/_pydevd_bundle/pydevd_runpy.py", line 321, in run_path
    return _run_module_code(code, init_globals, run_name,
  File "/Users/juliuseners/.vscode/extensions/ms-python.python-2022.16.1/pythonFiles/lib/python/debugpy/_vendored/pydevd/_pydevd_bundle/pydevd_runpy.py", line 135, in _run_module_code
    _run_code(code, mod_globals, init_globals,
  File "/Users/juliuseners/.vscode/extensions/ms-python.python-2022.16.1/pythonFiles/lib/python/debugpy/_vendored/pydevd/_pydevd_bundle/pydevd_runpy.py", line 124, in _run_code
    exec(code, run_globals)
  File "/Users/juliuseners/pythondir/Chapter 1.py", line 14, in <module>
    if dis>0:
TypeError: '>' not supported between instances of 'function' and 'int'

试过按照Homebrew的提示手动修改PATH，问题未解决。附上我运行的代码：

import math
#The quadratic is luckily solved for all coefficients a,b,c except for a=0: this diqualifies the equation as quadratic. 
#I write the function based on following formula: x=(-b+/-sqrt(b^2-4*a*c))/2a

a=input("Enter a: ")
b=input("Enter b: ")
c=input("Enter c: ")

def findmyroots(a,b,c):
   dis=b*b-4*a*c
   sqrtdis=math.sqrt(abs(dis))
if dis>0:
    print("The roots are:")
    print((-b+sqrtdis)/(2*a))
    print((-b-sqrtdis)/(2*a))
elif dis==0:
    print("The roots are:")
    print((-b)/(2*a))
else:
    print("Roots are lateral")

if a==0:
    print("Write a real quadratic please..")
else:1
    findmyroots(a,b,c)

根本不是环境变量的问题，全是代码本身的语法和逻辑错误，具体问题和修复如下：

1. 核心问题：变量作用域+缩进错误 #

• dis是定义在findmyroots函数内部的局部变量，函数外部的if dis>0:根本无法访问这个值。报错提示dis是函数类型，大概率是你之前的代码中定义过同名的dis函数，导致全局的dis被覆盖成了函数而非数值。
• 判断根的逻辑完全写在函数外面，没有在函数内部执行，等于逻辑无效。

2. 次要问题：输入未转换类型 #

input()获取的是字符串类型，直接用于数学运算会报错，必须转换为整数或浮点数。

3. 其他语法bug #

• else:1是无效语法，else后面需要跟缩进的代码块，不能直接写1。
• "Roots are lateral"描述错误，应该是复数根，改成中文描述更清晰。

修复后的完整代码 #

import math

# 二次方程求根公式：x=(-b±√(b²-4ac))/(2a)，a不能为0
a = float(input("请输入a的值："))
b = float(input("请输入b的值："))
c = float(input("请输入c的值："))

def findmyroots(a, b, c):
    dis = b**2 - 4*a*c
    sqrtdis = math.sqrt(abs(dis))
    
    if dis > 0:
        print("该方程有两个不同的实根：")
        print((-b + sqrtdis)/(2*a))
        print((-b - sqrtdis)/(2*a))
    elif dis == 0:
        print("该方程有一个重根：")
        print((-b)/(2*a))
    else:
        print("该方程有两个共轭复数根：")
        print(f"{-b/(2*a)} + {sqrtdis/(2*a)}i")
        print(f"{-b/(2*a)} - {sqrtdis/(2*a)}i")

if a == 0:
    print("请输入真正的二次方程（a不能为0）！")
else:
    findmyroots(a, b, c)

直接替换原代码，输入数值测试即可，比如输入a=1、b=-3、c=2，会输出根2和1，运行完全正常。

内容的提问来源于stack exchange，提问作者StudentNumberThreeXPlusOne