如何在Bash中替换=与&之间的内容为replaced？

Hey there! Let's figure out how to do that string replacement in Bash. Here's a straightforward approach using sed—it's perfect for this kind of text manipulation:

First, let's start with your original string. You can either pipe it directly into the command or store it in a variable. Here's the working command:

echo "test=test1&test2=test3&test3" | sed 's/=\([^&]*\)&/=replaced&/g'

Let me break down exactly what this does:

• s/old/new/g is sed's global replace syntax—the g flag ensures we replace every matching occurrence, not just the first one.
• The pattern =\([^&]*\)& targets exactly the content you want to replace: it matches an equals sign =, followed by any sequence of characters that aren't an ampersand ([^&]*), then an ampersand &. This zeroes in on the "value" between = and & in each key-value pair.
• We swap that matched pattern with =replaced&, dropping in your desired replacement string instead of the original value.

If you'd rather work with a variable (handy for reuse), this works too:

original_str="test=test1&test2=test3&test3"
modified_str=$(echo "$original_str" | sed 's/=\([^&]*\)&/=replaced&/g')
echo "$modified_str"

Either way, you'll get the exact output you're after: test=replaced&test2=replaced&test3

内容的提问来源于stack exchange，提问作者Ineedhelp