Roblox无法识别PyAutoGUI鼠标移动问题求助

我编写了一个Roblox断连自动重连脚本，通过ctypes读取屏幕像素判断是否触发断连状态，但遇到核心问题：Roblox无法识别PyAutoGUI的鼠标移动与点击操作，手动移动鼠标点击按钮则完全正常。脚本逻辑为：检测到断连标识像素后，等待网络恢复，自动点击重连按钮，但按钮无任何响应。

import pyautogui as py
import keyboard
import tkinter
import requests
from ctypes import windll
from time import sleep

key = "m"
toggled = False
rjcolor = 16777215

root = tkinter.Tk()
root.withdraw()

width, height = root.winfo_screenwidth(), root.winfo_screenheight()

dc= windll.user32.GetDC(0)

def getpixel(x,y):
    return windll.gdi32.GetPixel(dc,x,y)

while True:
    if keyboard.is_pressed(key):
        toggled = not toggled
        print("toggled to " + str(toggled))
        sleep(0.5)
    if toggled == True:
        py.moveTo(width / 2, 800)
        py.click(button='left')
        if getpixel(1050, 600) == rjcolor:
            print("disconnected, waiting until internet back online!")
            while True:
                try:
                    requests.head("http://www.google.com/", timeout=3)
                    print('The internet connection is active, rejoining.')
                    py.moveTo(1050, 590)
                    py.mouseDown(button='left')
                    sleep(0.1)
                    py.mouseUp(button='left')
                    break
                    
                except requests.ConnectionError:
                    print("The internet connection is down")
                sleep(3)
    sleep(0.1)

PyAutoGUI依赖Windows的SendInput API模拟输入，但Roblox等游戏会对上层模拟输入做拦截，优先识别硬件级别的鼠标操作，导致PyAutoGUI的操作无法被游戏捕捉。

使用ctypes直接调用Windows底层API模拟原生鼠标输入，绕过游戏的输入拦截。以下是修改后的完整代码，替换了PyAutoGUI的鼠标操作：

import keyboard
import tkinter
import requests
from ctypes import windll, c_uint
from time import sleep

# Windows API 常量定义
MOUSEEVENTF_MOVE = 0x0001
MOUSEEVENTF_LEFTDOWN = 0x0002
MOUSEEVENTF_LEFTUP = 0x0004
MOUSEEVENTF_ABSOLUTE = 0x8000

# 获取屏幕分辨率
root = tkinter.Tk()
root.withdraw()
SCREEN_WIDTH = root.winfo_screenwidth()
SCREEN_HEIGHT = root.winfo_screenheight()

# 初始化Windows API
user32 = windll.user32
gdi32 = windll.gdi32
dc = user32.GetDC(0)

def getpixel(x, y):
    return gdi32.GetPixel(dc, x, y)

def move_mouse(x, y):
    # 转换为绝对坐标（0-65535范围，适配Windows API要求）
    abs_x = int(x * 65535 / SCREEN_WIDTH)
    abs_y = int(y * 65535 / SCREEN_HEIGHT)
    user32.mouse_event(MOUSEEVENTF_MOVE | MOUSEEVENTF_ABSOLUTE, abs_x, abs_y, 0, 0)

def click_mouse(x, y):
    move_mouse(x, y)
    sleep(0.05)
    # 模拟左键按下+松开
    user32.mouse_event(MOUSEEVENTF_LEFTDOWN, 0, 0, 0, 0)
    sleep(0.1)
    user32.mouse_event(MOUSEEVENTF_LEFTUP, 0, 0, 0, 0)

# 脚本核心逻辑
key = "m"
toggled = False
rjcolor = 16777215

while True:
    if keyboard.is_pressed(key):
        toggled = not toggled
        print(f"toggled to {toggled}")
        sleep(0.5)
    if toggled:
        click_mouse(SCREEN_WIDTH / 2, 800)
        if getpixel(1050, 600) == rjcolor:
            print("disconnected, waiting until internet back online!")
            while True:
                try:
                    requests.head("http://www.google.com/", timeout=3)
                    print('The internet connection is active, rejoining.')
                    click_mouse(1050, 590)
                    break
                except requests.ConnectionError:
                    print("The internet connection is down")
                sleep(3)
    sleep(0.1)

1. 管理员权限运行：右键脚本选择“以管理员身份运行”，避免系统权限限制导致输入模拟失效。
2. 坐标校准：确保1050, 590等坐标与你屏幕上Roblox重连按钮的实际位置一致，可临时用pyautogui.displayMousePosition()获取坐标（仅用于校准，实际运行用修改后的代码）。
3. 颜色值验证：确认rjcolor = 16777215（纯白色）确实是断连状态下的标识像素颜色，避免误触发。

内容的提问来源于stack exchange，提问作者Piggy Gaming