如何在BeautifulSoup中跳过指定<li>标签迭代获取缩略图链接

思路一：按索引间隔遍历 #

直接只处理索引为0、3、6...的

from bs4 import BeautifulSoup
import requests
import openpyxl

try:
    response = requests.get("https://robloxden.com/item-codes")
    soup = BeautifulSoup(response.text, 'html.parser')
    items = soup.find('ul', class_="masonry masonry--5 item-codes__container").find_all("li")
 
    # 只遍历索引为0,3,6...的元素，步长设为3
    for index in range(0, len(items), 3):
        item = items[index]
        # 提取缩略图链接
        item_link = item.find('div', class_="image-card__graphic image-card__graphic--border-bottom").img
        if item_link:  # *额外增加判断，避免意外报错*
            print(item_link['data-src'])

except Exception as e:
    print(e)

思路二：判断标签是否含有效内容 #

遍历所有

from bs4 import BeautifulSoup
import requests
import openpyxl

try:
    response = requests.get("https://robloxden.com/item-codes")
    soup = BeautifulSoup(response.text, 'html.parser')
    items = soup.find('ul', class_="masonry masonry--5 item-codes__container").find_all("li")
 
    for item in items:
        # 先尝试找到目标div和img
        graphic_div = item.find('div', class_="image-card__graphic image-card__graphic--border-bottom")
        if graphic_div and graphic_div.img:
            item_link = graphic_div.img['data-src']
            print(item_link)

except Exception as e:
    print(e)

两种思路都能解决问题，第一种更贴合你已知的分组规律，效率更高；第二种更通用，就算页面结构小范围变动也能适配。

内容的提问来源于stack exchange，提问作者Ammar_Fahmy