如何计算输入的三个数中最大值与最小值的平均值？

核心问题分析 #

你现有代码中的largest和smallest函数仅负责打印结果，没有返回最大值、最小值的数值，导致无法直接调用这两个值计算平均值。解决的关键是让函数返回对应数值，再基于返回值完成平均值计算。

分步解决方法 #

1. 修改函数，添加返回值
   在现有函数末尾添加return语句，将找到的最大值、最小值返回，而非仅打印：

   def largest(num1, num2, num3):
       if (num1 > num2) and (num1 > num3):
           largest_num = num1
       elif (num2 > num1) and (num2 > num3):
           largest_num = num2
       else:
           largest_num = num3
       print("The largest of the 3 numbers is : ", largest_num)
       return largest_num  # 返回最大值
   
   def smallest(num1, num2, num3):
       if (num1 < num2) and (num1 < num3):
           smallest_num = num1
       elif (num2 < num1) and (num2 < num3):
           smallest_num = num2
       else:
           smallest_num = num3
       print("The smallest of the 3 numbers is : ", smallest_num)
       return smallest_num  # 返回最小值
   

2. 获取数值并计算平均值
   调用修改后的函数，接收返回的最大值、最小值，用(最大值 + 最小值) / 2计算平均值并打印：

完整代码示例 #

number1 = int(input('Enter First number : '))
number2 = int(input('Enter Second number : '))
number3 = int(input('Enter Third number : '))

def largest(num1, num2, num3):
    if (num1 > num2) and (num1 > num3):
        largest_num = num1
    elif (num2 > num1) and (num2 > num3):
        largest_num = num2
    else:
        largest_num = num3
    print("The largest of the 3 numbers is : ", largest_num)
    return largest_num

def smallest(num1, num2, num3):
    if (num1 < num2) and (num1 < num3):
        smallest_num = num1
    elif (num2 < num1) and (num2 < num3):
        smallest_num = num2
    else:
        smallest_num = num3
    print("The smallest of the 3 numbers is : ", smallest_num)
    return smallest_num

# 获取最大、最小值
max_num = largest(number1, number2, number3)
min_num = smallest(number1, number2, number3)

# 计算并打印平均值
average = (max_num + min_num) / 2
print(f"The average of largest and smallest numbers is : {average}")

简化方案（可选） #

如果不需要自定义找最大最小值的逻辑，直接用Python内置的max()和min()函数可以大幅精简代码：

number1 = int(input('Enter First number : '))
number2 = int(input('Enter Second number : '))
number3 = int(input('Enter Third number : '))

max_num = max(number1, number2, number3)
min_num = min(number1, number2, number3)

print("The largest of the 3 numbers is : ", max_num)
print("The smallest of the 3 numbers is : ", min_num)

average = (max_num + min_num) / 2
print(f"The average of largest and smallest numbers is : {average}")

内容的提问来源于stack exchange，提问作者Jaxjo