如何在Karate中统计列表重复值？karate.distinct()报错求助

方法1：遍历列表直接统计次数 #

通过遍历目标列表，维护一个计数Map来记录每个元素的出现次数，示例代码如下：

* def list = [
  "Cloud Services - Hybrid and Azure",
  "Cloud Services - Hybrid and Azure",
  "Cloud Services - Hybrid and Azure",
  "Cloud Services - Hybrid and Azure",
  "Application Development",
  "Application Development",
  "Application Development",
  "CAB Approval"
]
* def countMap = {}
* karate.forEach(list, function(item){
    countMap[item] = (countMap[item] || 0) + 1
  })
* print countMap

执行后会输出包含各元素出现次数的Map，其中"Cloud Services - Hybrid and Azure"对应的值即为4。

方法2：结合HashSet去重后统计 #

你之前用HashSet获取唯一值的思路可行，但写法有误，正确的实现方式如下：

* def list = [
  "Cloud Services - Hybrid and Azure",
  "Cloud Services - Hybrid and Azure",
  "Cloud Services - Hybrid and Azure",
  "Cloud Services - Hybrid and Azure",
  "Application Development",
  "Application Development",
  "Application Development",
  "CAB Approval"
]
* def uniqueItems = new java.util.HashSet(list)
* def countMap = {}
* karate.forEach(uniqueItems, function(item){
    countMap[item] = karate.filter(list, function(x){ return x == item }).length
  })
* print countMap

这段代码先通过HashSet得到所有唯一元素，再逐个统计每个元素在原列表中的出现次数。

关于karate.distinct()的说明 #

karate.distinct()仅用于返回列表的去重结果，不负责统计次数。如果使用时报错，需确认传入的参数是标准JSON数组，正确用法示例：

* def distinctList = karate.distinct(list)
* print distinctList // 输出 ["Cloud Services - Hybrid and Azure", "Application Development", "CAB Approval"]

内容的提问来源于stack exchange，提问作者user20485356