如何在Jython中将数组按原顺序均分为两个等长数组

需求说明 #

将长度为160的原数组按原有顺序分割为两个各包含80个元素的数组。

原数组 #

original_array = [325, 1127, 546, 721, 840, 613, 1036, 1001, 581, 926, 25, 508, 1188, 1104, 295, 994, 192,274, 1135, 632, 547, 185, 837, 669, 98, 564, 313, 43,975, 962, 409, 668, 598, 384, 703, 375, 841, 519, 593, 647, 1026, 1178, 307, 319, 1119, 381, 907, 1010, 758, 158, 280, 403, 599, 352, 190, 738,821, 1087, 506, 636, 672, 122, 203, 433, 630, 1049, 490, 265, 880, 378, 904, 261, 1056, 499, 483, 768, 1033, 510, 231, 1099, 567, 753, 1156, 96,82, 246, 675, 1213, 167, 1117, 930, 714, 1042, 299, 812, 575, 1146, 798, 405, 885, 1180, 462, 1210, 172, 754, 119, 91, 200, 1199, 127, 687, 452, 788, 52, 733, 713, 83, 1123, 68, 24, 722, 1029, 605, 585, 1171, 542, 1084, 652, 958, 839, 191, 699, 219,1096, 1216, 974, 1211, 1196, 1118, 497, 764, 1141, 346, 125, 390, 1066, 1016, 199, 932, 129, 230, 84, 27, 110, 806, 637, 769, 401, 1191, 211]

分割实现代码 #

在Jython中直接利用列表切片即可完成分割，代码如下：

# 分割为两个等长数组
array1 = original_array[:80]
array2 = original_array[80:]

# 输出结果
print("Array 1 =", array1)
print("Array 2 =", array2)

分割结果 #

Array 1 = [325, 1127, 546, 721, 840, 613, 1036, 1001, 581, 926, 25, 508, 1188, 1104, 295, 994, 192,274, 1135, 632, 547, 185, 837, 669, 98, 564, 313, 43,975, 962, 409, 668, 598, 384, 703, 375, 841, 519, 593, 647, 1026, 1178, 307, 319, 1119, 381, 907, 1010, 758, 158, 280, 403, 599, 352, 190, 738,821, 1087, 506, 636, 672, 122, 203, 433, 630, 1049, 490, 265, 880, 378, 904, 261, 1056, 499, 483, 768, 1033, 510, 231, 1099]
Array 2 = [567, 753, 1156, 96,82, 246, 675, 1213, 167, 1117, 930, 714, 1042, 299, 812, 575, 1146, 798, 405, 885, 1180, 462, 1210, 172, 754, 119, 91, 200, 1199, 127, 687, 452, 788, 52, 733, 713, 83, 1123, 68, 24, 722, 1029, 605, 585, 1171, 542, 1084, 652, 958, 839, 191, 699, 219,1096, 1216, 974, 1211, 1196, 1118, 497, 764, 1141, 346, 125, 390, 1066, 1016, 199, 932, 129, 230, 84, 27, 110, 806, 637, 769, 401, 1191, 211]

内容的提问来源于stack exchange，提问作者max092012