Python统计字符串中长度小于5的单词数量求助

原代码存在两个核心问题：

• 错误将单词列表words与字符串'1,2,3,4'做相等判断，两者类型、内容完全不匹配，永远无法触发统计逻辑
• 定义了letterCount字典但未实际利用，也没有遍历单词去判断长度条件

简洁实现版本 #

text = "It is a long established fact that a reader will be distracted by the readable content of a page when looking at its layout."
words = text.split()
count = sum(1 for word in words if len(word) < 5)
print(count)

分步理解版本 #

text = "It is a long established fact that a reader will be distracted by the readable content of a page when looking at its layout."
words = text.split()
count = 0
# 遍历每个单词，判断长度是否小于5
for word in words:
    if len(word) < 5:
        count += 1
print(count)

逻辑说明 #

1. 用split()将原字符串按空格分割为单词列表
2. 遍历列表中的每个单词，检查其长度是否小于5
3. 每找到一个符合条件的单词，计数器count加1
4. 最后输出统计得到的整数结果

内容的提问来源于stack exchange，提问作者Ruby