如何检查列表元素是否包含另一列表元素的子串并拼接结果

需求说明 #

遍历list1中的每个元素，检查该元素是否作为子串存在于list2的元素中；若存在，则将list2中所有包含该子串的字符串拼接为一个新字符串，添加到list3中。

输入示例 #

list1 = ["2044","1222"]
list2 = ["I am Raman 2044","I am Raman 2044","I am Raman 2044","I am Rohan 1222","I am Rohan 1222"]

注：原输入中的"I am Raman 2044"x属于输入笔误，已修正为正常字符串格式

输出示例 #

list3 = ["I am Raman 2044I am Raman 2044I am Raman 2044","I am Rohan 1222I am Rohan 1222"]

实现代码（Python） #

list1 = ["2044","1222"]
list2 = ["I am Raman 2044","I am Raman 2044","I am Raman 2044","I am Rohan 1222","I am Rohan 1222"]
list3 = []

for keyword in list1:
    # 筛选list2中包含当前关键词的所有字符串
    matched_items = [item for item in list2 if keyword in item]
    # 拼接后加入list3
    list3.append(''.join(matched_items))

print(list3)

内容的提问来源于stack exchange，提问作者Raman