如何将JSON对象的非规范键格式化为合规的标准键

需求说明 #

我有一个JSON对象，其中的键名不符合规范（包含空格、首字母大写等），需要将这些键名格式化为符合要求的形式，具体示例如下：

原JSON #

{
  "language": {
    "blogs details": "blogs details",
    "Search products": "Search products",
    "Somethings went wrong": "Somethings went wrong",
    "Become seller": "Become seller",
    "Cart": "Cart",
    "Your name": "Your Name",
    "Checkout": "Checkout"
  }
}

期望得到的JSON #

{
  "language": {
    "blogs_details": "blogs details",
    "search_products": "Search products",
    "Somethings_went_wrong": "Somethings went wrong",
    "become_seller": "Become seller",
    "cart": "Cart",
    "your_name": "Your Name",
    "checkout": "Checkout"
  }
}

解决方案 #

可以用JavaScript编写递归函数处理，核心逻辑是遍历JSON的每个键，将空格替换为下划线，同时把键名的首字母转为小写（仅修改键的第一个字符，后续单词的首字母保留原格式）。

代码实现 #

function normalizeJsonKeys(obj) {
  if (typeof obj !== 'object' || obj === null) {
    return obj;
  }
  if (Array.isArray(obj)) {
    return obj.map(item => normalizeJsonKeys(item));
  }
  const normalizedObj = {};
  for (const key in obj) {
    if (Object.prototype.hasOwnProperty.call(obj, key)) {
      // 替换空格为下划线，首字母转小写
      let normalizedKey = key.replace(/\s+/g, '_');
      normalizedKey = normalizedKey.charAt(0).toLowerCase() + normalizedKey.slice(1);
      normalizedObj[normalizedKey] = normalizeJsonKeys(obj[key]);
    }
  }
  return normalizedObj;
}

// 测试示例
const originalJson = {
  "language": {
    "blogs details": "blogs details",
    "Search products": "Search products",
    "Somethings went wrong": "Somethings went wrong",
    "Become seller": "Become seller",
    "Cart": "Cart",
    "Your name": "Your Name",
    "Checkout": "Checkout"
  }
};

const normalizedJson = normalizeJsonKeys(originalJson);
console.log(JSON.stringify(normalizedJson, null, 2));

代码说明 #

• 递归处理：支持嵌套的JSON对象和数组，确保所有层级的键都被规范化
• 键名转换规则：
  1. 用正则/\s+/g将所有空格替换为下划线
  2. 仅将键名的第一个字符转为小写，后续字符保留原格式（比如"Somethings went wrong"转为"Somethings_went_wrong"）

内容的提问来源于stack exchange，提问作者Ali