Python Hangman游戏：如何将下划线替换为猜对的字母？

核心问题在于Python的字符串是不可变类型，没法直接修改单个字符，所以我们可以把completion转成列表来操作，修改后再转回字符串。以下是补全并修改后的代码：

import random
  
# 读取单词文件并随机选择单词
with open("Words.txt", "r") as file:
    words = file.read().split()
    word = random.choice(words)

# 初始化变量
guessed_letters = ""
guessed_words = ""
completion = list("_" * len(word))  # 转成列表方便修改
lives = 8

# 游戏主循环
while lives > 0 and "_" in completion:
    print("\n当前进度: " + "".join(completion))
    print(f"剩余生命: {lives}")
    guess = input("请猜一个字母或单词: ").lower()

    # 处理重复猜测
    if guess in guessed_letters or guess in guessed_words:
        print("你已经猜过这个内容了，请换一个。")
        continue

    # 猜测单词的情况
    if len(guess) > 1:
        guessed_words += guess + " "
        if guess == word:
            completion = list(word)
            print("恭喜你猜对单词了！")
        else:
            lives -= 1
            print(f"猜错了，剩余生命: {lives}")
        continue

    # 猜测字母的情况
    guessed_letters += guess + " "
    if guess in word:
        # 遍历单词每个位置，替换对应下划线
        for i in range(len(word)):
            if word[i] == guess:
                completion[i] = guess
        print("猜对字母了！")
    else:
        lives -= 1
        print(f"猜错了，剩余生命: {lives}")

# 游戏结束判断
if "_" not in completion:
    print(f"\n游戏胜利！正确单词是: {word}")
else:
    print(f"\n游戏失败！正确单词是: {word}")

关键修改说明 #

• 把completion初始化为列表：completion = list("_" * len(word))，这样可以直接修改指定位置的元素
• 当猜对字母时，遍历目标单词的每个索引，匹配到相同字母就替换列表对应位置的元素
• 用"".join(completion)把列表转回字符串，方便打印显示
• 增加了游戏主循环，处理多次猜测、重复猜测、单词猜测等完整逻辑

Words.txt 文件内容 #

banana
nike
jordan
game
whole
hole
hi
hello

内容的提问来源于stack exchange，提问作者Gamingwithjack 777