Python中Try/Except无法捕获pycountry_convert特定异常问题

你的代码异常捕获逻辑失效的核心原因是：异常变量e是Exception对象，不是字符串，直接用e == "Invalid Country Alpha-2 code: 'TL'"进行比较永远不成立，导致无法触发东帝汶的特殊处理分支，只能返回'N/A'。

方案一：提前判断国家代码（推荐） #

在调用大陆转换函数前，先检查东帝汶的Alpha-2代码'TL'，直接返回对应的大陆编码'AS'，无需触发异常，代码更高效清晰：

import pycountry_convert as pc

def pegacontinente(nomepais):
    nomepais = nomepais.replace("-", " ")
    ignore_words = ['and', 'the']
    nomepais = ' '.join([word.capitalize() if word not in ignore_words else word for word in nomepais.split()])
    try:
        country_code = pc.country_name_to_country_alpha2(nomepais, cn_name_format="default")
        # 提前处理东帝汶的特殊情况
        if country_code == 'TL':
            return 'AS'
        return pc.country_alpha2_to_continent_code(country_code)
    except Exception:
        return 'N/A'

方案二：正确匹配异常字符串 #

如果必须通过异常捕获处理，需要将Exception对象转换为字符串后再进行匹配：

import pycountry_convert as pc

def pegacontinente(nomepais):
    nomepais = nomepais.replace("-", " ")
    ignore_words = ['and', 'the']
    nomepais = ' '.join([word.capitalize() if word not in ignore_words else word for word in nomepais.split()])
    try:
        country_code = pc.country_name_to_country_alpha2(nomepais, cn_name_format="default")
        continent_name = pc.country_alpha2_to_continent_code(country_code)
    except Exception as e:
        # 将异常对象转为字符串后匹配
        if str(e) == "Invalid Country Alpha-2 code: 'TL'":
            continent_name = 'AS'
        else:
            continent_name = 'N/A'
    return continent_name

内容的提问来源于stack exchange，提问作者Yuri Reis Valete