如何根据学生姓名返回对应负责教师姓名（解决索引输出问题）

问题说明 #

现有代码已经能通过findIndex定位到学生所在班级的索引，但需要把索引映射到teachers数组中对应的教师姓名，替代当前直接返回索引的输出结果。

修改方案 #

只需要在获取到班级索引后，用该索引从teachers数组中取出对应教师姓名即可，同时可以补充学生不存在的处理逻辑，避免输出undefined。

修改后的完整代码 #

let teachers = ["Arrington", "Kincart", "Alberts", "Pickett"]
let rooms = [
  ["Andy", "Rodolfo", "Lynn", "Talia"],
  ["Al", "Ross", "Jorge", "Dante"],
  ["Nick", "Kim", "Jasmine", "Dorothy"],
  ["Adam", "Grayson", "Aliyah", "Alexa"]
]
let whichTeacher = (student) => {
    // 获取学生所在班级的索引
    const classIndex = rooms.findIndex(row => row.indexOf(student) !== -1);
    // 找到索引则返回对应教师，否则返回提示
    return classIndex !== -1 ? teachers[classIndex] : "未找到该学生对应的班级";
}
console.log(`The teacher who has Jorge is ${whichTeacher("Jorge")}.`)
console.log(`The teacher who has Alexa is ${whichTeacher("Alexa")}.`)

运行输出结果 #

The teacher who has Jorge is Kincart.
The teacher who has Alexa is Pickett.

关键改动点 #

• 将获取到的班级索引存入变量classIndex，清晰区分索引获取与教师姓名映射的逻辑
• 增加三元判断处理学生不存在的边界场景，提升代码健壮性
• 通过teachers[classIndex]完成从班级索引到教师姓名的转换

内容的提问来源于stack exchange，提问作者user19444313