如何在Discord.py交互中发送多个带图片的Embed？

实现Discord交互命令时，根据howmany参数指定次数发送带图片的Embed，但仅第一个Embed显示图片，后续Embed无法加载图片。当前交互命令代码如下：

@tree.command(name='embed', description='embed')
async def embed(interaction: discord.Interaction, seeable: bool, howmany: typing.Optional[int]):
    embed = discord.Embed(title="Here is a title", color=0xff8c00)
    file = discord.File(f"[file path]", filename="image.png")
    embed.set_image(url="attachment://image.png")
    if seeable == True:
        await interaction.response.send_message(file=file, embed=embed)
        if howmany >= 2:
            for i in range(howmany-1):
                await interaction.followup.send(file=file, embed=embed)
    if seeable == False:
        await interaction.response.send_message(file=file, embed=embed, ephemeral=True)
        if howmany >= 2:
            for i in range(howmany-1):
                await interaction.followup.send(file=file, embed=embed, ephemeral=True)

旧前缀系统下功能正常（使用远程图片URL），代码示例：

if message.content.startswith('+image'):
    count = 0
    args = message.content.split(' ')
    if len(args) < 2:
        count = 1
    else:
        if args[1].isdigit():
            count = int(args[1])
        else:
            await message.channel.send("How many should it be?")
    for i in range(count):
        random = random.randint(1,68)
        embed = discord.Embed(title="Title", color=0xff8c00)
        embed.set_image(url=f"https://www.awebsite/pic{random}.png")
        # file = discord.File(f"C:a/file/path/pic{random}.png", filename="image.png")
        # embed.set_image(url="attachment://image.png")
        # await message.channel.send(file=file, embed=embed)
        await message.channel.send(embed=embed)

discord.File对象只能被Discord API处理一次，复用同一个File实例发送后续消息时，Discord不会重新上传该文件，导致后续Embed中的attachment://image.png找不到对应的附件资源。旧前缀系统使用远程URL时，每个Embed直接指向独立的远程资源，因此没有这个问题。

每次发送消息（包括初始响应和后续跟进消息）时，重新创建discord.File实例，确保每次请求都携带有效的文件附件。

修改后的代码示例：

@tree.command(name='embed', description='embed')
async def embed(interaction: discord.Interaction, seeable: bool, howmany: typing.Optional[int]):
    # 处理howmany默认值，避免参数为None的情况
    howmany = howmany or 1
    
    def create_embed_with_file():
        # 每次调用生成全新的File和Embed实例
        file = discord.File(f"[file path]", filename="image.png")
        embed = discord.Embed(title="Here is a title", color=0xff8c00)
        embed.set_image(url="attachment://image.png")
        return file, embed

    if seeable:
        # 发送初始响应
        file, embed = create_embed_with_file()
        await interaction.response.send_message(file=file, embed=embed)
        # 发送后续消息
        for _ in range(howmany - 1):
            file, embed = create_embed_with_file()
            await interaction.followup.send(file=file, embed=embed)
    else:
        # 发送仅自己可见的初始响应
        file, embed = create_embed_with_file()
        await interaction.response.send_message(file=file, embed=embed, ephemeral=True)
        # 发送仅自己可见的后续消息
        for _ in range(howmany - 1):
            file, embed = create_embed_with_file()
            await interaction.followup.send(file=file, embed=embed, ephemeral=True)

• 封装create_embed_with_file函数是为了避免重复代码，确保每次发送都生成全新的File和Embed实例，保证附件有效性。
• 增加howmany = howmany or 1处理参数为None的情况，确保至少发送1次消息。

内容的提问来源于stack exchange，提问作者lorenzfohl