Python初学者求助：为何触发IndexError: list assignment index out of range错误

你的问题出在直接通过索引给空列表或无对应位置的列表赋值。Python里，空列表[]或者[]*5（这玩意儿还是空列表，因为空列表乘任何数都是空）根本没有x对应的索引位置，自然会抛IndexError。

给你几个可行的解决办法：

方法1：用append()添加元素 #

这是最直观也最常用的方式，直接把拼接好的名字追加到列表末尾：

player_first_name = ["Luka", "Nikola", "Giannis", "Stephen", "Jayson"]
player_last_name = ["Doncic", "Jokic", "Antetokounmpo", "Curry", "Tatum"]
player = []

for x in range(5):
    full_name = player_first_name[x] + " " + player_last_name[x]
    player.append(full_name)

方法2：预先初始化指定长度的列表 #

如果一定要用索引赋值，得先给列表每个索引位置预留空间，比如用[None] * 5创建一个长度为5、每个元素都是None的列表，之后就能通过索引赋值了：

player_first_name = ["Luka", "Nikola", "Giannis", "Stephen", "Jayson"]
player_last_name = ["Doncic", "Jokic", "Antetokounmpo", "Curry", "Tatum"]
player = [None] * 5  # 初始化长度为5的列表

for x in range(5):
    player[x] = player_first_name[x] + " " + player_last_name[x]

方法3：用列表推导式（更简洁） #

一行搞定，Pythonic的写法：

player_first_name = ["Luka", "Nikola", "Giannis", "Stephen", "Jayson"]
player_last_name = ["Doncic", "Jokic", "Antetokounmpo", "Curry", "Tatum"]

player = [f"{first} {last}" for first, last in zip(player_first_name, player_last_name)]

这里用zip()把两个列表的元素一一配对，再用f-string拼接名字，比循环更简洁高效。

顺便提一句，你之前试的player = [] *5没用，因为空列表乘以任何整数结果还是空列表，只有非空列表乘以数才会重复元素扩展长度。

内容的提问来源于stack exchange，提问作者maxpower8888