如何通过Python的input函数获取返回值？技术求助

你的代码核心问题是input()函数默认返回字符串类型，但你在判断逻辑里用它和整数100、200做比较，类型不匹配导致两个if分支都不会触发。下面给你两种修改方案：

方案一：将输入转换为整数（推荐，支持后续数值操作） #

把输入的字符串转成整数，同时添加异常处理，避免用户输入非数字内容时程序报错：

def bike_wash(amount):
    print("Welcome to your bike wash")
    print("Please enter your desired wash")
    
    if amount == 100:
        print("Thanks for choosing basic wash")
        print("Enjoy water wash with spray")
    elif amount == 200:
        print("Thanks for choosing Premium wash")
        print("Enjoy foam wash to the entire body")
    else:
        print("Invalid amount, please enter 100 or 200")

try:
    amount = int(input("Enter wash amount: "))
    bike_wash(amount)
except ValueError:
    print("Please enter a valid number")

方案二：将判断条件改为字符串比较 #

如果不需要对amount做数值计算，直接把判断里的整数改成字符串即可：

def bike_wash(amount):
    print("Welcome to your bike wash")
    print("Please enter your desired wash")
    
    if amount == "100":
        print("Thanks for choosing basic wash")
        print("Enjoy water wash with spray")
    elif amount == "200":
        print("Thanks for choosing Premium wash")
        print("Enjoy foam wash to the entire body")
    else:
        print("Invalid amount, please enter 100 or 200")

amount = input("Enter wash amount: ")
bike_wash(amount)

另外建议把两个独立的if改成elif（避免逻辑冗余），同时新增else分支处理无效输入的情况，让程序更健壮。

内容的提问来源于stack exchange，提问作者Nitin Srivastav