求助：如何改写不含break语句的Python循环代码？

以下是去掉所有break语句后的代码，通过控制变量和循环条件替代原逻辑：

import random

# 假设check_win和print_table是已定义的游戏核心函数
def check_win(table):
    # 示例胜利判定逻辑，可根据实际游戏规则调整
    for row in table:
        if all(cell == "SEEN" for cell in row):
            return True
    for col in range(3):
        if all(table[row][col] == "SEEN" for row in range(3)):
            return True
    if table[0][0] == table[1][1] == table[2][2] == "SEEN":
        return True
    if table[0][2] == table[1][1] == table[2][0] == "SEEN":
        return True
    return False

def print_table(table):
    for row in table:
        print(" | ".join(row))
    print()

# 初始化示例数据（可根据实际需求替换）
contents = ["A", "B", "C", "D", "E", "F", "G", "H", "I"]
table = [["A", "B", "C"], ["D", "E", "F"], ["G", "H", "I"]]

game_active = True
while game_active:
    choice = input("Is it time to choose(Y/N)? ")
    if choice.upper() == "N": 
        game_active = False
    else:
        # 修正原代码潜在索引越界问题：randint为闭区间，范围应设为0到len(contents)-1
        idx = random.randint(0, len(contents)-1)
        fnd = False
        i = 0
        # 用while循环+条件替代外层for的break
        while i < 3 and not fnd:
            j = 0
            # 用while循环+条件替代内层for的break
            while j < 3 and not fnd:
                if table[i][j] == contents[idx]:
                    table[i][j] = "SEEN"
                    fnd = True
                j += 1
            i += 1
        won = check_win(table)
        print_table(table)
        if won:
            print("The game has been won!!")
            game_active = False

关键改动说明： #

• 外层循环控制：用game_active布尔变量替代while True的无限循环，当输入"N"或游戏胜利时，将game_active设为False，循环自动终止。
• 嵌套查找逻辑：把原双层for循环改为while循环，通过fnd变量和计数器范围（i < 3、j < 3）控制循环是否继续。找到目标位置后fnd变为True，后续循环条件不满足，自然退出，完全替代原break的功能。
• 索引修复：原代码中random.randint(0, len(contents))会触发列表索引越界（列表最大索引为len(contents)-1），已同步修正范围。

内容的提问来源于stack exchange，提问作者A Z