如何保持输出行顺序不变，对同频次统计单词按字母排序？

我编写了一段用于统计文本文件中高频单词的Python代码：

words = open(input('Enter the name of the file: ')).read().lower().split()
number_of_words = int(input('Enter how many top words you want to see: '))
uniques = []
stop_words = ["a", "an", "and", "in", "is"]
for word in words:
  check_special = False
  if word.isalnum():
    check_special = True
  if word not in uniques and word not in stop_words and check_special:
    uniques.append(word)

counts = []
for unique in uniques:
  count = 0
  for word in words:
    if word == unique:
      count += 1
  counts.append((count, unique))

counts.sort()
counts.reverse()

counts_dict = {count: [] for count, word in counts}
for count, word in counts:
    counts_dict[count].append(word)
    sorted_count = sorted(counts_dict)

count_num_word = 0
for count in counts_dict:
    if count_num_word >= number_of_words:
        break
    print('The following words appeared %d times each: %s' % (count, ', '.join(counts_dict[count])))
    count_num_word += 1

当前输出示例：

The following words appeared 8 times each: what, just, apple

我希望在不改变输出行顺序（仍按频次从高到低排列）的前提下，将每行“each:”后的单词按字母顺序排列，得到如下输出：

The following words appeared 8 times each: apple, just, what

解决方案 #

有两种简单的实现方式：

方式一：提前对每个频次的单词列表排序

在构建完counts_dict之后，添加一段循环对每个频次对应的单词列表进行字母排序：

# 在for count, word in counts:循环之后，输出循环之前添加
for count in counts_dict:
    counts_dict[count].sort()

修改后的完整代码片段：

counts_dict = {count: [] for count, word in counts}
for count, word in counts:
    counts_dict[count].append(word)
    sorted_count = sorted(counts_dict)

# 新增排序逻辑
for count in counts_dict:
    counts_dict[count].sort()

count_num_word = 0
for count in counts_dict:
    if count_num_word >= number_of_words:
        break
    print('The following words appeared %d times each: %s' % (count, ', '.join(counts_dict[count])))
    count_num_word += 1

方式二：输出时直接排序

不需要修改字典结构，直接在输出时对当前频次的单词列表进行排序：
将原print语句替换为：

print('The following words appeared %d times each: %s' % (count, ', '.join(sorted(counts_dict[count]))))

两种方式都能保证同频次单词按字母顺序排列，同时输出行仍保持按频次从高到低的顺序（Python 3.7及以上版本的字典会保留键的插入顺序，这里counts已经按频次降序排列，所以counts_dict的键顺序符合要求）。

内容的提问来源于stack exchange，提问作者thenorthape