猜数字游戏程序优化需求：实现祝贺后循环直至输入0退出

以下是调整逻辑后的代码，实现猜对数字后自动开启新一局，直到输入0退出：

import random
import datetime

e = datetime.datetime.now()
print(e.strftime("%B %d,%Y @ %H:%M:%S"))

name = input("\nEnter your name: ")
 
def main():
    while True:
        # 每局生成新的随机数
        number = random.randint(1, 100)
        print(f"\nHi, {name}, Welcome to the Guessing Number Game ")
        x = eval(input("Enter a number between 1 and 100, or 0 to quit: "))
        if x == 0:
            print("You quit? Goodbye!")
            break
        # 调用猜数字函数，若中途退出则终止循环
        if not playGuessingGame(x, number):
            break

def playGuessingGame(x, number):
    times = 1
    while number != x:
        if x == 0:
            print("You quit? Goodbye!")
            return False
        times += 1
        if x < number:
            print("Too low, try again")
            x = eval(input("Enter a number between 1 and 100, or 0 to quit: "))
        elif x > number:
            print("Too high, try again")
            x = eval(input("Enter a number between 1 and 100, or 0 to quit: "))
    
    print(f"Congratulations {name}!, you guessed the right number with {times} tries!")
    # 猜对后返回True，触发新一局
    return True

main()

关键调整说明 #

• 全局随机数改局内生成：把number = random.randint(1,100)移到main的循环里，保证每局都是不同的随机数
• 循环式游戏流程：main函数用while True包裹，猜对后自动进入下一局，输入0则执行break退出
• 中途退出处理：在playGuessingGame中增加对输入0的判断，中途输入0时返回False，让main循环终止
• 函数参数传递：把每局的随机数number作为参数传给playGuessingGame，避免全局变量耦合
• 移除测试打印：删掉了原代码中用于测试的print(number)语句，正常游戏不会泄露答案

内容的提问来源于stack exchange，提问作者IA Nadir