如何实现石头剪刀布游戏三轮对局？解决循环重复结果问题

你的代码核心问题是循环逻辑位置错误：你把获取用户选择和电脑随机选择的代码放在了for循环外面，这意味着这两个值只会被初始化一次，三轮循环都重复使用同一组选择，所以每次输出结果完全相同。

要实现真正的三轮独立对局，需要把get_user_input()和random_choice()的调用放到for循环内部，让每一轮都重新获取用户输入、生成电脑的新随机选择。

修改后的完整代码 #

import random

OPTIONS = ["Rock", "Paper", "Scissors"]

def get_user_input():
    user_choice = input("Select your play (Rock, Paper or Scissors): ")
    return user_choice

def random_choice():
    computer_choice = random.choice(OPTIONS)
    return computer_choice

def game(user_choice, computer_choice):
    if user_choice == computer_choice:
        print(f"You selected: {user_choice}.\nComputer selected: {computer_choice}.\nDraw.")
    else:
        if computer_choice == "Rock" and user_choice == "Paper":
            print(f"You selected: {user_choice}.\nComputer selected: {computer_choice}.\nYou won!")
        if computer_choice == "Rock" and user_choice == "Scissors":
            print(f"You selected: {user_choice}.\nComputer selected: {computer_choice}.\nYou lost...")
        if computer_choice == "Paper" and user_choice == "Scissors":
            print(f"You selected: {user_choice}.\nComputer selected: {computer_choice}.\nYou won!")
        if computer_choice == "Paper" and user_choice == "Rock":
            print(f"You selected: {user_choice}.\nComputer selected: {computer_choice}.\nYou lost...")
        if computer_choice == "Scissors" and user_choice == "Rock":
            print(f"You selected: {user_choice}.\nComputer selected: {computer_choice}.\nYou won!")
        if computer_choice == "Scissors" and user_choice == "Paper":
            print(f"You selected: {user_choice}.\nComputer selected: {computer_choice}.\nYou lost...")

def main():
    # 将输入和随机选择放入循环，每轮重新生成
    for round_num in range(3):
        print(f"\n--- 第{round_num+1}轮对局 ---")
        user_choice = get_user_input()
        computer_choice = random_choice()
        game(user_choice, computer_choice)
    print("\n三轮游戏全部结束！")

main()

额外优化建议 #

1. 增加输入校验：判断用户输入是否在OPTIONS列表内，避免无效输入导致逻辑异常
2. 简化胜负判断逻辑：用字典替代大量重复的if语句，让代码更简洁，比如：

# 定义玩家获胜的对应关系：键是玩家选择，值是能击败的电脑选择
WIN_RULES = {
    "Rock": "Scissors",
    "Paper": "Rock",
    "Scissors": "Paper"
}

def game(user_choice, computer_choice):
    print(f"You selected: {user_choice}.\nComputer selected: {computer_choice}.")
    if user_choice == computer_choice:
        print("Draw.")
    elif WIN_RULES[user_choice] == computer_choice:
        print("You won!")
    else:
        print("You lost...")

内容的提问来源于stack exchange，提问作者Adrià Martínez