如何根据name与name0的匹配结果返回对应输入数据子集

核心逻辑 #

1. 提取输入数据中的name和name0字段值进行比较
2. 若两者相等，返回所有带0后缀的键值对；若不等，返回所有不带0后缀的键值对

Python 实现 #

def filter_data(input_data):
    main_name = input_data.get('name')
    suffix_name = input_data.get('name0')
    
    if main_name == suffix_name:
        return {k: v for k, v in input_data.items() if k.endswith('0')}
    else:
        return {k: v for k, v in input_data.items() if not k.endswith('0')}

# 测试用例
input_data = {
  "Dv type": None,
  "Environment": None,
  "ipa": None,
  "category": None,
  "name": "ALPHA009",
  "Dv type0": "NYC",
  "Environment0": "sev",
  "ipa0": "X.Y.1",
  "category0": "test",
  "name0": "APLHA009"
}

print(filter_data(input_data))

JavaScript 实现 #

function filterData(inputData) {
    const mainName = inputData.name;
    const suffixName = inputData.name0;
    
    if (mainName === suffixName) {
        return Object.fromEntries(
            Object.entries(inputData).filter(([key]) => key.endsWith('0'))
        );
    } else {
        return Object.fromEntries(
            Object.entries(inputData).filter(([key]) => !key.endsWith('0'))
        );
    }
}

// 测试用例
const inputData = {
  "Dv type": null,
  "Environment": null,
  "ipa": null,
  "category": null,
  "name": "ALPHA009",
  "Dv type0": "NYC",
  "Environment0": "sev",
  "ipa0": "X.Y.1",
  "category0": "test",
  "name0": "APLHA009"
};

console.log(filterData(inputData));

内容的提问来源于stack exchange，提问作者samrathal