日期区间合并技术求助：按连续日期规则合并时间记录

我有一组包含开始日期（started）和结束日期（stop）的记录：

合并规则 #

需要合并满足以下时间顺序的记录：前一条记录的结束日期 = 后一条记录的开始日期 + 1天

预期合并结果 #

我尝试通过检查日期差为1天来分组记录，但得到了异常结果。以下是我编写的Python代码：

import datetime

class Records:

    def __init__(self, start_dt, stop_dt):
        self.groupNum = None
        self.dayDiff = None
        self.start_dt = start_dt
        self.stop_dt = stop_dt

    def setGroupNum(self, groupNum):
        self.groupNum = groupNum

    def setdayDiff(self, dayDiff):
        self.dayDiff = dayDiff

def main():
    recordsLst = []
    resultLst = []

    recordsLst.append(Records(datetime.date(2017, 8, 14), datetime.date(2018, 3, 5)))
    recordsLst.append(Records(datetime.date(2019, 1, 14), datetime.date(2019, 3, 6)))
    recordsLst.append(Records(datetime.date(2019, 3, 7), datetime.date(2019, 3, 20)))
    recordsLst.append(Records(datetime.date(2023, 12, 30), datetime.date(9999, 12, 31)))
    recordsLst.append(Records(datetime.date(2020, 9, 8), datetime.date(2020, 9, 14)))
    recordsLst.append(Records(datetime.date(2020, 9, 15), datetime.date(2020, 10, 14)))
    recordsLst.append(Records(datetime.date(2019, 3, 21), datetime.date(2019, 3, 30)))
    recordsLst.sort(key=lambda x: x.start_dt, reverse=False)
    
    for index, a in enumerate(recordsLst):
        for b in recordsLst[index:]:
            # 如果是同一条记录
            if (a.start_dt.day == b.start_dt.day and
                a.start_dt.month == b.start_dt.month and
                a.start_dt.year == b.start_dt.year) and \
                    (a.stop_dt.day == b.stop_dt.day and
                     a.stop_dt.month == b.stop_dt.month and
                     a.stop_dt.year == b.stop_dt.year):
                a.setGroupNum('same')
            # 如果符合时间顺序
            if a.stop_dt.month == b.start_dt.month \
                    and a.stop_dt.year == b.start_dt.year \
                    and (a.stop_dt.day - b.start_dt.day) == -1:
                a.setdayDiff(-1)
                a.setGroupNum(index)
                # 注：Datum未定义，此处为原代码笔误
                # resultLst.append(Datum(a.stop_dt, b.start_dt))
            else:
                a.setdayDiff(None)
            print(index, a, b)

if __name__ == "__main__":
    main()

另外还有一个新的Pandas数据集：

import pandas as pd
import datetime

df = pd.DataFrame([[datetime.date(2016, 1, 2),   datetime.date(2016, 5, 5)],

                   # 案例 A->B, B->C, B->D => A->D
                   [datetime.date(2010, 2, 14),   datetime.date(2010, 3, 22)],
                   [datetime.date(2010, 3, 23),   datetime.date(2010, 4, 12)],
                   [datetime.date(2010, 3, 23),   datetime.date(2010, 5, 14)],
                   [datetime.date(2010, 5, 15),   datetime.date(2010, 6, 7)],
                   # -> 2010-02-14 | 2010-10-20

                   # 案例 A->B, A->C, B->D => A->D
                   [datetime.date(2011, 1, 1),   datetime.date(2011, 2, 2)],
                   [datetime.date(2011, 1, 1),   datetime.date(2011, 3, 4)],
                   [datetime.date(2011, 2, 3),   datetime.date(2011, 4, 4)],
                   # -> 2011-01-01 | 2011-04-04

                   # 案例 A->C, B->C, C->D => A->D
                   [datetime.date(2012, 5, 5),   datetime.date(2012, 6, 6)],
                   [datetime.date(2012, 5, 7),   datetime.date(2012, 6, 6)],
                   [datetime.date(2012, 6, 7),   datetime.date(2012, 12, 12)],
                   # -> 2012-05-05 | 2012-12-12

                   [datetime.date(2010, 6, 8),   datetime.date(2010, 10, 20)],
                   [datetime.date(2016, 5, 6),   datetime.date(2016, 10, 10)],
                   [datetime.date(2011, 1, 1),   datetime.date(9999, 12, 31)]],
                  columns=['start', 'end'])

恳请各位提供帮助，谢谢！

内容的提问来源于stack exchange，提问作者Rody