Python 3 条件判断（if-else）程序编译错误求助

Let's walk through the issues in your code and fix them up:

Key Issues Identified #

• Variable Case Mismatch: You initialized your variable as lowercase n (n = int(input().strip())), but used uppercase N in every condition check. Python is case-sensitive, so it treats n and N as two entirely different variables. This will trigger a NameError since N was never defined.
• Python 3 print Syntax: In Python 3, print is a built-in function, which means you need to wrap the output string in parentheses. Your code uses the old Python 2 syntax (print "Weird"), which will cause a syntax error.

Corrected Code #

n = int(input().strip())
if n % 2 != 0:
    print("Weird")
else:
    if n >= 2 and n <= 5:
        print("Not Weird")
    elif n >= 6 and n <= 20:
        print("Weird")
    elif n > 20:
        print("Not Weird")

Quick Explanation #

• We replaced all instances of N with n to match the variable you defined.
• Added parentheses around all print statements to comply with Python 3's function syntax.
• The logic itself is correct once these syntax issues are fixed—your conditions for determining "Weird" vs "Not Weird" work as intended.

内容的提问来源于stack exchange，提问作者A Singh