Python报错TypeError: input最多接受1个参数却传入3个，如何修复？

First, let's break down why you're hitting that error:

TypeError: input expected at most 1 arguments, got 3

The input() function only accepts a single string as its argument. When you use commas to split your prompt ("type number ",n+1," : value "), you're passing three separate values to input() instead of one combined string. That's exactly what's causing the error.

How to Fix It #

You need to merge your prompt text and variable into a single string. Here are three straightforward ways to do this in Python:

1. Use F-Strings (Recommended for Python 3.6+)

F-strings are the cleanest and most readable option for formatting strings with variables. Just add an f before your quoted string, and wrap variables in curly braces {}:

n = int(input("type how many input : "))
if n != 0:
    small = int(input("type number 1 value : "))
    for i in range(1, n):
        # Combine text and variable with an f-string
        temp = int(input(f"type number {i+1} : value "))
        if temp < small:
            small = temp
print(small)

2. Use str.format()

If you're working with an older Python version (pre-3.6), use the format() method to insert variables into your string:

n = int(input("type how many input : "))
if n != 0:
    small = int(input("type number 1 value : "))
    for i in range(1, n):
        temp = int(input("type number {} : value ".format(i+1)))
        if temp < small:
            small = temp
print(small)

3. String Concatenation with +

You can also glue strings together using the + operator, but you'll need to convert the integer i+1 to a string first with str():

n = int(input("type how many input : "))
if n != 0:
    small = int(input("type number 1 value : "))
    for i in range(1, n):
        temp = int(input("type number " + str(i+1) + " : value "))
        if temp < small:
            small = temp
print(small)

Bonus Fix: Correcting the Prompt Number #

I noticed your original code used n+1 in the prompt, which would show the same incorrect number every time (e.g., if n=3, it would always say "number 4"). Changing it to i+1 ensures each prompt displays the right sequential number (2, 3, ..., n) for each input.

Edge Case Note #

Your code handles n=0 by skipping the input loop, but when n=0, print(small) will throw a NameError because small isn't defined. To fix this, you could initialize small to a default value and add a check before printing:

n = int(input("type how many input : "))
small = None
if n != 0:
    small = int(input("type number 1 value : "))
    for i in range(1, n):
        temp = int(input(f"type number {i+1} : value "))
        if temp < small:
            small = temp
if small is not None:
    print(small)
else:
    print("No numbers were entered.")

内容的提问来源于stack exchange，提问作者The Temp Guy