猜数字游戏Python代码运行逻辑异常问题咨询

问题根源 #

你代码里的核心问题是每次循环都会重新生成随机目标数字——random.randint(1,10)被放在了while循环内部，导致用户每猜一次，正确答案就换了一个。这就解释了为什么你根据提示猜6时，结果还是不对：因为这次的目标数字已经不是之前那个了。

修复后的代码 #

import random
print("lets play the game")
print("you will be given 3 chances to play the game")
i = 1
score = 0

# 把目标数字生成移到循环外，确保3次机会猜同一个数
c = random.randint(1, 10)

while(i <= 3):
    d = int(input("enter your choice: "))
    if(d == c):
        score += 1
        print("congrats it was the correct guess")
        print(f"you have {3 - i} chances left +1")
    elif(d > c):
        print(" oops !!your choice was too high")
        print(f"you have {3 - i} chances left,better luck next time")
    elif(d < c):
         print(" oops !!your choice was too low")
         print(f"you have {3 - i} chances left,better luck next time")
    i += 1

print(f"your score is {score}")

修复说明 #

把c = random.randint(1,10)移到while循环之前后，整个游戏的3次机会都会围绕同一个固定的目标数字进行，用户根据前一次的提示（过高/过低）调整猜测时，逻辑就完全通顺了。

内容的提问来源于stack exchange，提问作者vaishnavi kumari