Swift中如何合并数组重复对象并累加对应属性值？

云上老周

2026-8-8

同名对象积分累加并去重实现方案

你可以通过临时映射表的方式实现，比嵌套循环更高效（时间复杂度O(n)），具体步骤和代码如下：

核心思路

用一个映射结构（对象或Map）存储每个名字对应的总积分，利用键的唯一性自动去重
遍历原数组，累加同名对象的points值
将映射结构转换为目标格式的数组

JavaScript 实现示例

方法一：使用普通对象作为映射表

const persons = [
  { "name": "Daniel", "points": 10 },
  { "name": "Ana", "points": 20 },
  { "name": "Daniel", "points": 40 }
];

const pointsMap = {};
// 遍历累加积分
persons.forEach(person => {
  if (pointsMap[person.name]) {
    pointsMap[person.name] += person.points;
  } else {
    pointsMap[person.name] = person.points;
  }
});

// 转换为目标数组
const result = Object.entries(pointsMap).map(([name, points]) => ({
  name,
  points
}));

console.log(result);
// 输出：[{"name":"Daniel","points":50},{"name":"Ana","points":20}]

方法二：使用`Map`（更适合含特殊字符的名字）

const persons = [
  { "name": "Daniel", "points": 10 },
  { "name": "Ana", "points": 20 },
  { "name": "Daniel", "points": 40 }
];

const pointsMap = new Map();
// 遍历累加积分
persons.forEach(person => {
  const currentTotal = pointsMap.get(person.name) || 0;
  pointsMap.set(person.name, currentTotal + person.points);
});

// 转换为目标数组
const result = Array.from(pointsMap, ([name, points]) => ({ name, points }));

console.log(result);