如何通过Python批量订阅YouTube频道（基于Channel_ID）

问题原因 #

你当前代码里的字典存在键重复问题：'snippet.resourceId.channelId'被赋值两次，后一个值会直接覆盖前一个，所以只会执行最后一个频道的订阅请求。

修改方案 #

我们需要把频道ID整理成一个列表，然后循环调用订阅函数，逐个处理每个频道：

完整修改后的代码 #

import os
import time
import google.oauth2.credentials
import google_auth_oauthlib.flow
from googleapiclient.discovery import build
from googleapiclient.errors import HttpError
from google_auth_oauthlib.flow import InstalledAppFlow

CLIENT_SECRETS_FILE = "client_secret.json"
SCOPES = ['https://www.googleapis.com/auth/youtube.force-ssl']
API_SERVICE_NAME = 'youtube'
API_VERSION = 'v3'

def get_authenticated_service():
    flow = InstalledAppFlow.from_client_secrets_file(CLIENT_SECRETS_FILE, SCOPES)
    credentials = flow.run_console()
    return build(API_SERVICE_NAME, API_VERSION, credentials=credentials)

def print_response(response):
    print(f"成功订阅频道: {response['snippet']['resourceId']['channelId']}")

def build_resource(properties):
    resource = {}
    for p in properties:
        prop_array = p.split('.')
        ref = resource
        for pa in range(len(prop_array)):
            is_array = False
            key = prop_array[pa]
            if key[-2:] == '[]':
                key = key[:-2]
                is_array = True
            if pa == len(prop_array) - 1:
                if properties[p]:
                    if is_array:
                        ref[key] = properties[p].split(', ')
                    else:
                        ref[key] = properties[p]
            elif key not in ref:
                ref[key] = {}
                ref = ref[key]
            else:
                ref = ref[key]
    return resource

def remove_empty_kwargs(**kwargs):
    good_kwargs = {}
    if kwargs:
        for key, value in kwargs.items():
            if value:
                good_kwargs[key] = value
    return good_kwargs

def subscriptions_insert(client, channel_id):
    # 针对单个频道构建订阅参数
    properties = {
        'snippet.resourceId.kind': 'youtube#channel',
        'snippet.resourceId.channelId': channel_id
    }
    resource = build_resource(properties)
    kwargs = remove_empty_kwargs(part='snippet')
    try:
        response = client.subscriptions().insert(body=resource, **kwargs).execute()
        print_response(response)
    except HttpError as e:
        print(f"订阅频道 {channel_id} 失败: {e}")

if __name__ == '__main__':
    os.environ['OAUTHLIB_INSECURE_TRANSPORT'] = '1'
    client = get_authenticated_service()
    
    # 把需要订阅的所有频道ID放在这个列表里
    channel_ids = [
        'UC09fL42MpkktKZWmWxYiDhw',
        'UC0Q7Hlz75NYhYAuq6O0fqHw',
        # 继续添加更多频道ID即可
    ]
    
    # 循环遍历列表，逐个订阅（加入延时避免API限流）
    for channel_id in channel_ids:
        subscriptions_insert(client, channel_id)
        time.sleep(1)

关键修改点 #

• 将多个频道ID存入列表channel_ids，彻底解决字典键覆盖问题
• 重构subscriptions_insert函数，改为接收单个频道ID作为参数，每次只处理一个订阅请求
• 增加异常捕获，处理订阅失败的情况（比如频道不存在、权限不足等）
• 添加time.sleep(1)避免API请求过于频繁触发限流，适配470+订阅的批量操作
• 优化打印信息，明确显示每个频道的订阅状态

扩展建议 #

如果要从旧账号迁移全部订阅：

• 可以调用YouTube数据API的subscriptions.list接口，获取旧账号的所有订阅频道ID，直接导入到channel_ids列表中
• 若订阅数量极大，可将频道ID存入文本文件，通过读取文件批量加载，避免代码里硬编码过多内容

内容的提问来源于stack exchange，提问作者Dan