Python文本元音直方图开发需求：需显示零值元音并统计"the"次数

import string
lowercase_letters = list(string.ascii_lowercase)
uppercase_letters = list(string.ascii_uppercase)
letters = lowercase_letters + uppercase_letters
user_input = input()  # 避免变量名与导入的string模块冲突
stri = user_input.lower()
if not(user_input.replace(' ', '').isalpha()):
    exit()
else:
    counted_the = stri.count("the")
    chars = [char for char in stri if char != " " and char in letters]
    vowels = {"a": 0, "e": 0, "i": 0, "o": 0, "u": 0}
    for key, value in vowels.items():
        counted = chars.count(key)
        vowels[key] = counted
        # 所有元音统一输出，不再过滤计数为0的情况
        if counted == 0:
            print(f"{key}: 0")
        else:
            print(f"{key}: {'*' * counted}")
    if counted_the == 0:
        print("zero")
    else:
        print(counted_the)

• 移除了原代码中仅打印计数大于0元音的判断逻辑，确保每个元音（包括未出现的）都会输出对应信息：计数为0时显示元音: 0，计数大于0时显示元音: 对应数量的*
• 将变量名string改为user_input，避免与导入的string模块重名引发潜在冲突
• 其余原有功能逻辑保持不变，满足不使用函数的要求

内容的提问来源于stack exchange，提问作者Alireza Bagheri