如何在SwiftUI中处理UIViewControllerRepresentable封装的TableViewController导航？

方法一：使用SwiftUI原生导航机制（推荐） #

这种方式更贴合SwiftUI的设计范式，将跳转逻辑交给SwiftUI统一处理，避免混合UIKit导航带来的兼容性问题：

1. 修改ContactView，添加绑定属性跟踪选中的联系人：

struct ContactView: UIViewControllerRepresentable {
    let viewModel: ContactsViewModel
    @Binding var selectedContact: Contact? // 替换为你的联系人模型类型

    func makeUIViewController(context: Context) -> ContactsTableViewController {
        let vc = ContactsTableViewController(viewModel: viewModel)
        vc.tableView.delegate = context.coordinator
        return vc
    }

    func updateUIViewController(_ uiViewController: ContactsTableViewController, context: Context) {
    }
}

2. 更新Coordinator，选中联系人时修改绑定状态：

extension ContactView {
    class Coordinator: NSObject, UITableViewDelegate {
        var parent: ContactView

        init(_ parent: ContactView) {
            self.parent = parent
        }

        func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath) {
            let contact = parent.viewModel.contacts[indexPath.row]
            parent.selectedContact = contact
            tableView.deselectRow(at: indexPath, animated: true)
        }
    }

    func makeCoordinator() -> Coordinator {
        Coordinator(self)
    }
}

3. 在SwiftUI主视图中用NavigationStack处理跳转：
   如果详情页是UIKit的DetailViewController，先将其包装为UIViewControllerRepresentable：

struct DetailViewRepresentable: UIViewControllerRepresentable {
    let contact: Contact

    func makeUIViewController(context: Context) -> DetailViewController {
        let dependencies = DetailsViewModel.Dependencies(
            contacts: parent.viewModel.contacts,
            contactMethod: contact.contactMethod
        )
        let viewModel = DetailsViewModel(dependencies: dependencies)
        return viewModel.detailViewControllerFactory(viewModel.contacts, contact.contactMethod)
    }

    func updateUIViewController(_ uiViewController: DetailViewController, context: Context) {
    }
}

然后在主视图中配置导航：

struct MainContentView: View {
    @State private var selectedContact: Contact?
    let viewModel: ContactsViewModel

    var body: some View {
        NavigationStack {
            ContactView(viewModel: viewModel, selectedContact: $selectedContact)
                .navigationDestination(item: $selectedContact) { contact in
                    DetailViewRepresentable(contact: contact)
                }
        }
    }
}

方法二：直接使用UIKit导航控制器推送 #

如果需要保留UIKit的pushViewController逻辑，可以通过获取宿主视图控制器的导航引用实现：

1. 给Coordinator添加ContactsTableViewController的引用：

extension ContactView {
    class Coordinator: NSObject, UITableViewDelegate {
        var parent: ContactView
        weak var hostVC: ContactsTableViewController? // 宿主视图控制器引用

        init(_ parent: ContactView) {
            self.parent = parent
        }

        func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath) {
            let contact = parent.viewModel.contacts[indexPath.row]
            
            // 创建详情视图控制器
            let dependencies = DetailsViewModel.Dependencies(
                contacts: parent.viewModel.contacts,
                contactMethod: contact.contactMethod
            )
            let viewModel = DetailsViewModel(dependencies: dependencies)
            let detailsViewController = viewModel.detailViewControllerFactory(viewModel.contacts, contact.contactMethod)
            
            // 获取导航控制器并推送
            if let navController = hostVC?.navigationController {
                navController.pushViewController(detailsViewController, animated: true)
            }
            tableView.deselectRow(at: indexPath, animated: true)
        }
    }

    func makeCoordinator() -> Coordinator {
        Coordinator(self)
    }
}

2. 在makeUIViewController中给Coordinator赋值宿主VC：

func makeUIViewController(context: Context) -> ContactsTableViewController {
    let vc = ContactsTableViewController(viewModel: viewModel)
    vc.tableView.delegate = context.coordinator
    context.coordinator.hostVC = vc // 传递宿主VC引用
    return vc
}

注意：此方法要求ContactView必须嵌入在SwiftUI的NavigationStack（iOS 15及以下用NavigationView）中，否则navigationController会返回nil。

内容的提问来源于stack exchange，提问作者onthemoon