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如何访问列表中每个对象的body属性并检查特定单词是否存在

问题分析与解决

你的代码存在两处核心问题,下面逐一修正:

1. 数组定义语法错误

j_list数组内部不能用const post = {...}声明对象,直接写入对象字面量即可。

修正后的j_list:

const j_list = [
  {
    "postId": 1,
    "id": 1,
    "name": "id labore ex et quam laborum",
    "email": "Eliseo@gardner.biz",
    "body": "laudantium enim quasi est quidem magnam voluptate ipsam eos\ntempora quo necessitatibus\ndolor quam autem quasi\nreiciendis et nam sapiente accusantium"
  },
  {
    "postId": 1,
    "id": 2,
    "name": "quo vero reiciendis velit similique earum",
    "email": "Jayne_Kuhic@sydney.com",
    "body": "est natus enim nihil est dolore omnis voluptatem numquam\net omnis occaecati quod ullam at\nvoluptatem error expedita pariatur\nnihil sint nostrum voluptatem reiciendis et"
  },
  {
    "postId": 1,
    "id": 3,
    "name": "odio adipisci rerum aut animi",
    "email": "Nikita@garfield.biz",
    "body": "quia molestiae reprehenderit quasi aspernatur\naut expedita occaecati aliquam eveniet laudantium\nomnis quibusdam delectus saepe quia accusamus maiores nam est\ncum et ducimus et vero voluptates excepturi deleniti ratione"
  }
];

2. 循环与字符串检查逻辑错误

  • for...in遍历数组时拿到的是索引字符串,不是数组中的post对象,因此post.body会报错,应改用for...of遍历数组元素,或forEach方法。
  • includes()方法直接返回布尔值,不需要和-1比较(indexOf()才会返回索引,找不到时返回-1)。

方案一:使用for...of循环

for (const post of j_list) {
  if (post.body.includes("quasi")) {
    console.log("This post contains that word");
  } else {
    console.log("This post doesn't contain any search word");
  }
}

方案二:使用forEach方法

j_list.forEach(post => {
  if (post.body.includes("quasi")) {
    console.log("This post contains that word");
  } else {
    console.log("This post doesn't contain any search word");
  }
});

兼容旧环境的传统for循环

for (let i = 0; i < j_list.length; i++) {
  const post = j_list[i];
  if (post.body.includes("quasi")) {
    console.log("This post contains that word");
  } else {
    console.log("This post doesn't contain any search word");
  }
}

内容的提问来源于stack exchange,提问作者Thestrike95

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最近更新时间:2026.08.08 14:20:28