使用Kutana框架时pickle序列化Game类对象报错求助

我正在使用Kutana框架，相关代码如下：

plugins/test.py #

from kutana import Plugin
import pickle

plugin = Plugin(name="Tictactoe",
                description="Tictactoe Game",
                invites={},
                games=[])


@plugin.on_start()
async def _():
    plugin.games = [Game()]


# Backup games when bot is shutting down
@plugin.on_shutdown()
async def _():
    try:
        with open("games.pickle", "wb") as f:
            pickle.dump(plugin.games, f)
    except Exception as e:
        print(e)


class Game:
    def __init__(self):
        pass

run.py #

from kutana import Kutana, load_plugins

# Create application
app = Kutana()

# Load and register plugins
app.add_plugins(load_plugins("plugins/"))

if __name__ == "__main__":
    # Run application
    app.run()

当plugin.games为空时，pickle可正常序列化；但放入Game类实例后，备份时会报错：

Traceback (most recent call last):
  File "C:\Users\root\Desktop\Celestiana\plugins\games\tictactoe.py", line 17, in _
    pickle.dump(pl.games, f)
_pickle.PicklingError: Can't pickle <class 'plugins/games\tictactoe.py.Game'>: import of module 'plugins/games\\tictactoe.py' failed

我尝试使用pickle.dump(plugin.games, f, fix_imports=True)但无效，请问该如何修复？

方法一：将Game类移到独立可导入模块 #

1. 在plugins目录下创建game_classes.py文件，存放Game类：

# plugins/game_classes.py
class Game:
    def __init__(self):
        pass

2. 在plugins/test.py中相对导入该类：

from kutana import Plugin
import pickle
from .game_classes import Game  # 相对导入

plugin = Plugin(name="Tictactoe",
                description="Tictactoe Game",
                invites={},
                games=[])

# 后续代码保持不变

3. 确保plugins目录下有__init__.py（空文件即可），让Python识别为合法包。

方法二：手动修正类的模块路径 #

如果不想拆分模块，可在Game类定义后手动设置__module__属性，让pickle能正确识别模块路径：

class Game:
    def __init__(self):
        pass

# 根据你的插件实际路径设置，比如插件是games/tictactoe.py就写"plugins.games.tictactoe"
Game.__module__ = "plugins.test"

内容的提问来源于stack exchange，提问作者user14038884