如何在不遍历主数组的情况下移除嵌套结构中的isCorrect属性

我有一个包含对象的数组，希望在不手动遍历主数组且不将属性值改为false的前提下，移除所有键为"isCorrect"的属性。

示例数组 #

[ { "arrangement": 1, "question": "mijn", "answers": [ { "answer": "nmiou", "isCorrect": true }, { "answer": "nkj", "isCorrect": false }, { "answer": "nk", "isCorrect": false }, { "answer": "jln", "isCorrect": false } ] }, { "arrangement": 2, "question": "kjn", "answers": [ { "answer": "kjn", "isCorrect": true }, { "answer": "kj", "isCorrect": false }, { "answer": "nkj", "isCorrect": false }, { "answer": "n", "isCorrect": false } ] }, { "arrangement": 3, "question": "jn", "answers": [ { "answer": "n", "isCorrect": true }, { "answer": "n", "isCorrect": false }, { "answer": "n", "isCorrect": false }, { "answer": "nn", "isCorrect": false } ] }, { "arrangement": 4, "question": "n", "answers": [ { "answer": "n", "isCorrect": true }, { "answer": "n", "isCorrect": false }, { "answer": "n", "isCorrect": false }, { "answer": "n", "isCorrect": false } ] }, { "arrangement": 5, "question": "n", "answers": [ { "answer": "n", "isCorrect": true }, { "answer": "n", "isCorrect": false }, { "answer": "n", "isCorrect": false }, { "answer": "n", "isCorrect": false } ] }, { "arrangement": 6, "question": "nn", "answers": [ { "answer": "n", "isCorrect": true }, { "answer": "n", "isCorrect": false }, { "answer": "n", "isCorrect": false }, { "answer": "n", "isCorrect": false } ] }, { "arrangement": 7, "question": "n", "answers": [ { "answer": "n", "isCorrect": true }, { "answer": "n", "isCorrect": false }, { "answer": "n", "isCorrect": false }, { "answer": "n", "isCorrect": false } ] }, { "arrangement": 8, "question": "n", "answers": [ { "answer": "n", "isCorrect": true }, { "answer": "nkokj", "isCorrect": false }, { "answer": "nj", "isCorrect": false }, { "answer": "nkj", "isCorrect": false } ] }, { "arrangement": 9, "question": "n", "answers": [ { "answer": "njk", "isCorrect": true }, { "answer": "nkjn", "isCorrect": false }, { "answer": "jk", "isCorrect": false }, { "answer": "nkj", "isCorrect": false } ] }, { "arrangement": 10, "question": "i", "answers": [ { "answer": "i", "isCorrect": true }, { "answer": "ii", "isCorrect": false }, { "answer": "i", "isCorrect": false }, { "answer": "i", "isCorrect": false } ] } ]

补充说明 #

用手动循环可以实现需求，但会消耗额外的时间与性能。以下是仅修改属性值的示例代码（非目标实现）：

let primaryArray = [ { "arrangement": 3, "question": "jn", "answers": [ { "answer": "n", "isCorrect": true }, { "answer": "n", "isCorrect": false }, { "answer": "n", "isCorrect": false }, { "answer": "nn", "isCorrect": false } ] }, { "arrangement": 4, "question": "n", "answers": [ { "answer": "n", "isCorrect": true }, { "answer": "n", "isCorrect": false }, { "answer": "n", "isCorrect": false }, { "answer": "n", "isCorrect": false } ] }, { "arrangement": 5, "question": "n", "answers": [ { "answer": "n", "isCorrect": true }, { "answer": "n", "isCorrect": false }, { "answer": "n", "isCorrect": false }, { "answer": "n", "isCorrect": false } ] }, { "arrangement": 6, "question": "nn", "answers": [ { "answer": "n", "isCorrect": true }, { "answer": "n", "isCorrect": false }, { "answer": "n", "isCorrect": false }, { "answer": "n", "isCorrect": false } ] }, { "arrangement": 7, "question": "n", "answers": [ { "answer": "n", "isCorrect": true }, { "answer": "n", "isCorrect": false }, { "answer": "n", "isCorrect": false }, { "answer": "n", "isCorrect": false } ] }, { "arrangement": 8, "question": "n", "answers": [ { "answer": "n", "isCorrect": true }, { "answer": "nkokj", "isCorrect": false }, { "answer": "nj", "isCorrect": false }, { "answer": "nkj", "isCorrect": false } ] }, { "arrangement": 9, "question": "n", "answers": [ { "answer": "njk", "isCorrect": true }, { "answer": "nkjn", "isCorrect": false }, { "answer": "jk", "isCorrect": false }, { "answer": "nkj", "isCorrect": false } ] }, { "arrangement": 10, "question": "i", "answers": [ { "answer": "i", "isCorrect": true }, { "answer": "ii", "isCorrect": false }, { "answer": "i", "isCorrect": false }, { "answer": "i", "isCorrect": false } ] } ]

primaryArray.map((q)=>{
  q.answers[0].isCorrect = false;
})
console.log(primaryArray)

完全避免遍历是不现实的，但可以利用原生API的高效实现替代手动循环，既满足“不手动遍历主数组”的要求，又能高效移除目标属性。

方法1：利用JSON.stringify的替换器参数 #

通过JSON.stringify的replacer函数过滤掉isCorrect属性，再将字符串转回对象。原生JSON处理由引擎底层实现，性能通常优于手动循环：

const processedArray = JSON.parse(JSON.stringify(primaryArray, (key, value) => {
  if (key === 'isCorrect') return undefined;
  return value;
}));
console.log(processedArray);

说明：

• 该方法会创建原数组的深拷贝，不会修改原数组
• 无需手动编写循环逻辑，代码简洁

方法2：使用数组高阶方法隐式遍历 #

如果允许使用数组内置的高阶方法（内部仍会遍历，但无需手动编写循环），可以结合对象解构精准移除属性：

const processedArray = primaryArray.map(item => ({
  ...item,
  answers: item.answers.map(ans => {
    const { isCorrect, ...rest } = ans;
    return rest;
  })
}));
console.log(processedArray);

说明：

• 同样是深拷贝，不修改原数组
• 代码逻辑直观，便于后续维护，性能与原生JSON方法接近

内容的提问来源于stack exchange，提问作者Mohammad Abdulhakim