如何用正则表达式提取文本中所有UUID格式的ID？

Hey there! I see you're stuck trying to pull all those UUIDs from your JSON data—your current regex only grabs one, but we can fix that easily. Let's break down the solutions:

Option 1: Use a Precise Regex with Global Matching #

Your original regex is too vague ((\d*\w*-\d*\w*-\d*\w*-\d*\w*-\d*\w*)) and missing the global match flag, which is why it only returns the first UUID. Instead, use a regex tailored to UUID's standard 8-4-4-4-12 hex format:

[0-9a-f]{8}-[0-9a-f]{4}-[0-9a-f]{4}-[0-9a-f]{4}-[0-9a-f]{12}

Add flags to make it work globally and ignore case (since UUIDs might use uppercase letters):

• g (global): Matches all occurrences, not just the first
• i (ignore case): Captures both uppercase and lowercase hex characters

Example Implementation (JavaScript) #

If you're working in a browser or Node.js:

// Your JSON string (replace ... with full content if possible)
const jsonContent = `[
 {
 "id": "059ffad4-1f6f-4221-82bb-1a56ca709e28",
 "contentType": "tv",
 "Logo": null,
 "Large": "",
 "Medium": "",
 "Thumbnail": " https://imagesiwantnow.blob.core.windows.net/iwantnow/ott/episodes/2018-01-16/20141027-forevermore-289x163.jpg ",
 "title": "001 - Forevermore - Oct 27, 2014"
 },
 {
 "id": "dfb35a01-865d-4203-a31c-ff97a6a1fa51",
 "contentType": "tv",
 "Logo": null,
 "Large": "",
 "Medium": "",
 ...
]`;

// Extract all UUIDs
const allUuids = jsonContent.match(/[0-9a-f]{8}-[0-9a-f]{4}-[0-9a-f]{4}-[0-9a-f]{4}-[0-9a-f]{12}/gi);

// Add to a listbox (example for HTML)
const listbox = document.getElementById('yourListboxID');
allUuids.forEach(uuid => {
  const option = document.createElement('option');
  option.textContent = uuid;
  option.value = uuid;
  listbox.appendChild(option);
});

Example Implementation (Python) #

If you're using Python:

import re

# Your JSON content as a string
json_content = '''[
 {
 "id": "059ffad4-1f6f-4221-82bb-1a56ca709e28",
 "contentType": "tv",
 "Logo": null,
 "Large": "",
 "Medium": "",
 "Thumbnail": " https://imagesiwantnow.blob.core.windows.net/iwantnow/ott/episodes/2018-01-16/20141027-forevermore-289x163.jpg ",
 "title": "001 - Forevermore - Oct 27, 2014"
 },
 {
 "id": "dfb35a01-865d-4203-a31c-ff97a6a1fa51",
 "contentType": "tv",
 "Logo": null,
 "Large": "",
 "Medium": "",
 ...
]'''

# Extract all UUIDs
all_uuids = re.findall(r'[0-9a-f]{8}-[0-9a-f]{4}-[0-9a-f]{4}-[0-9a-f]{4}-[0-9a-f]{12}', json_content, re.IGNORECASE)

# Add to a Tkinter listbox
from tkinter import Tk, Listbox

root = Tk()
listbox = Listbox(root)
listbox.pack(padx=10, pady=10)

for uuid in all_uuids:
    listbox.insert('end', uuid)

root.mainloop()

Option 2: Parse the JSON Directly (More Reliable) #

If your JSON is complete (no ... truncation), parsing it directly is a safer approach—regex can break if the JSON structure changes.

Example (JavaScript) #

// Parse the JSON (ensure it's valid, remove ... first)
const data = JSON.parse(jsonContent);
const allUuids = data.map(item => item.id);

// Add to listbox same as before

Example (Python) #

import json

# Parse valid JSON (remove ... first)
data = json.loads(json_content)
all_uuids = [item['id'] for item in data]

# Add to listbox same as before

Why Your Original Regex Failed #

Your regex (\d*\w*-\d*\w*-\d*\w*-\d*\w*-\d*\w*) is overly broad (it matches any word/number combinations separated by dashes) and doesn't include a global match flag. Without g (in JS) or using findall (in Python), it stops after the first match.

内容的提问来源于stack exchange，提问作者zackmark29