如何根据玩家当前房间从字典中仅打印对应单个条目

我希望根据玩家当前所在房间位置，每次仅打印字典中对应的一组键值对，但目前尝试的所有方法要么打印全部条目，要么重复打印（次数等于条目总数），要么无任何输出。

我的房间字典代码 #

rooms = {
    'Lower Deck': {'up': 'Main Deck'},
    'Main Deck': {'down': 'Lower Deck', 'forward': 'Main Hallway', 'item': 'Pistol'},
    'Main Hallway': {'right': 'Crew Cabins', 'back': 'Main Deck', 'forward': 'Air Lock'},
    'Crew Cabins': {'back': 'Main Hallway', 'item': 'Dog tags'},
    'Air Lock': {'back': 'Main Hallway', 'forward': 'Crews Lounge'},
    'Crews Lounge': {'back': 'Air Lock', 'right': 'Escape pods', 'left': 'Engineering Room', 'up': 'Operation Room', 'item': 'Grenade'},
    'Escape pods': {'back': 'Crews Lounge'},
    'Engineering Room': {'back': 'Crews Lounge'},
    'Operation Room': {'back': 'Crews Lounge', 'forward': 'Control Center'},
    'Control Center': {'back': 'Operation Room'}
}

我尝试的代码（效果不好） #

for i in rooms:
    i = current_room
    print('The current exit to the room are: {}'.format(rooms[i]))

输出结果（重复打印当前房间内容，次数等于字典条目数）：

The current exit to the room are: {'up': 'Main Deck'}
The current exit to the room are: {'up': 'Main Deck'}
The current exit to the room are: {'up': 'Main Deck'}
...

可正常运行的房间移动代码 #

current_room = 'Lower Deck'
command = input("Please enter your move:\n").split()
if command[0].capitalize() == 'Go':
    if command[1] in directions:
        room_dict = rooms[current_room]
        if command[1] in room_dict:
            current_room = room_dict[command[1]]
        else:
            print("There is no exit that direction.\n")

解决方案 #

1. 核心问题：多余的for循环 #

你这段代码重复打印的原因是遍历了整个rooms字典的所有键，每次循环又把i强制赋值为current_room，所以字典有多少个房间，就会重复打印多少次当前房间的信息。直接去掉for循环，通过current_room直接取值即可。

2. 基础版：仅打印当前房间信息 #

不需要循环，一行代码就能搞定：

print(f'当前房间的出口信息：{rooms[current_room]}')

这样只会打印一次当前房间对应的键值对，不会重复。

3. 优化版：友好的信息展示 #

如果觉得直接打印字典不够直观，可以把出口和物品分开展示，提升体验：

current_room_data = rooms[current_room]
# 提取所有出口（排除item键）
exits = [direction for direction in current_room_data if direction != 'item']
print(f'\n你现在在：{current_room}')
print(f'可前往的方向：{", ".join(exits)}')
# 检查房间内是否有物品
if 'item' in current_room_data:
    print(f'房间里有：{current_room_data["item"]}')

4. 整合到游戏循环中 #

把展示房间信息的逻辑封装成函数，放到移动完成后调用，实现动态更新：

rooms = {
    'Lower Deck': {'up': 'Main Deck'},
    'Main Deck': {'down': 'Lower Deck', 'forward': 'Main Hallway', 'item': 'Pistol'},
    'Main Hallway': {'right': 'Crew Cabins', 'back': 'Main Deck', 'forward': 'Air Lock'},
    'Crew Cabins': {'back': 'Main Hallway', 'item': 'Dog tags'},
    'Air Lock': {'back': 'Main Hallway', 'forward': 'Crews Lounge'},
    'Crews Lounge': {'back': 'Air Lock', 'right': 'Escape pods', 'left': 'Engineering Room', 'up': 'Operation Room', 'item': 'Grenade'},
    'Escape pods': {'back': 'Crews Lounge'},
    'Engineering Room': {'back': 'Crews Lounge'},
    'Operation Room': {'back': 'Crews Lounge', 'forward': 'Control Center'},
    'Control Center': {'back': 'Operation Room'}
}

current_room = 'Lower Deck'
directions = ['up', 'down', 'forward', 'back', 'left', 'right']

def show_current_room():
    """展示当前房间的信息"""
    current_room_data = rooms[current_room]
    exits = [d for d in current_room_data if d != 'item']
    print(f'\n=== 当前位置：{current_room} ===')
    print(f'出口方向：{", ".join(exits)}')
    if 'item' in current_room_data:
        print(f'发现物品：{current_room_data["item"]}')

# 游戏开始时先显示初始房间
show_current_room()

# 主游戏循环
while True:
    command = input("\n请输入指令（格式：Go + 方向，或Quit退出）：\n").strip().split()
    if not command:
        continue
    cmd_head = command[0].capitalize()
    if cmd_head == 'Go':
        if len(command) < 2:
            print("请输入完整指令，例如：Go up")
            continue
        direction = command[1].lower()
        if direction in directions:
            if direction in rooms[current_room]:
                current_room = rooms[current_room][direction]
                show_current_room()
            else:
                print("那个方向没有出口！")
        else:
            print("无效方向，请输入：up/down/forward/back/left/right")
    elif cmd_head == 'Quit':
        print("游戏结束，再见！")
        break
    else:
        print("未知指令，请重新输入！")

内容的提问来源于stack exchange，提问作者Joe