Kotlin中如何移除JSON特定字段值的引号？

Hey there! Let's sort out that JSON formatting issue you're facing. The problem with your current code is that you're converting the JsonArray to a string and manually mucking with quotes, which forces the JSON serializer to treat your array as a plain string value (hence the extra quotes around [415918]). Instead, we should let the JSON library handle the array natively—no string replacements needed.

The Correct Approach #

Instead of converting your JsonArray to a string, pass the actual JsonArray object directly to JSONObject.put(). Here's the cleaned-up code:

// Step 1: Build your array normally
val array = JsonArray()
array.add(id.toString()) // Use array.add(id) if id is a numeric type instead

// Step 2: Create the inner JSON object with the array as a native value
val innerJson = JSONObject().apply {
    put("a", "value_a")
    put("b", "value_b")
    put("c", array) // No toString() or replace() here!
}

// Step 3: Wrap it in the outer testJson object
val testObj = JSONObject().apply {
    put("testJson", innerJson) // Again, pass the JSONObject directly
}

// Step 4: Get the final valid JSON string
val finalJsonString = testObj.toString()

What This Produces #

The resulting JSON will look exactly like you want:

{"testJson":{"a":"value_a","b":"value_b","c":["415918"]}}

Now the c field is a proper JSON array, not a quoted string.

Bonus: Use Modern Kotlin JSON Libraries (Even Easier!) #

If you're open to using more idiomatic Kotlin tools, libraries like kotlinx.serialization or Gson make this even cleaner and type-safe. Here's an example with kotlinx.serialization:

First, add the library dependencies (follow your project's setup guidelines), then define data classes:

import kotlinx.serialization.Serializable
import kotlinx.serialization.encodeToString
import kotlinx.serialization.json.Json

@Serializable
data class InnerPayload(
    val a: String = "value_a",
    val b: String = "value_b",
    val c: List<String>
)

@Serializable
data class TestPayload(val testJson: InnerPayload)

Then serialize your data in one line:

val payload = TestPayload(InnerPayload(c = listOf(id.toString())))
val finalJsonString = Json.encodeToString(payload)

This eliminates manual JSON construction entirely and reduces the chance of formatting errors.

内容的提问来源于stack exchange，提问作者Andrew