文本RPG定时器功能实现求助：超时未输入时程序自动退出

你的核心问题在于：threading.Timer 只是启动了一个独立线程执行打印操作，但主线程仍会一直阻塞在 input() 调用上，导致超时后用户依然能输入内容并继续游戏。要实现超时后强制终止程序、阻止用户继续交互的效果，需要让超时事件能打断主线程的输入等待。

下面是两种可行的实现方案：

方案一：使用 threading.Event 实现跨平台超时输入 #

通过事件对象标记超时状态，在输入流程中同步检查状态，超时则直接终止程序：

from threading import Timer, Event

timeout_event = Event()

def timed_exit():
    print('\nThe guards catch you. They execute you on the spot. You die.')
    timeout_event.set()
    exit()

def escape_scene():
    timeout = 5
    # 启动超时定时器
    t = Timer(timeout, timed_exit)
    t.start()
    
    decisions = ["left", "right", "up"]
    print("You walk into an opening filled with guards! Where do you go?")
    answer = ""
    while answer not in decisions:
        # 检查是否已触发超时
        if timeout_event.is_set():
            break
        print("Options: left/right/up")
        try:
            answer = input()
            # 用户成功输入，取消定时器
            t.cancel()
        except:
            pass
        
        if answer == "left":
            nothing()
        elif answer == "right":
            nothing()
        elif answer == "up":
            example()
        else:
            print("That is not an option.")
            # 递归重新进入场景前，先取消当前定时器
            t.cancel()
            escape_scene()

# 替换为你的实际游戏逻辑函数
def nothing():
    print("You chose left/right, nothing happens.")

def example():
    print("You climbed up and escaped!")

escape_scene()

方案二：使用 signal 模块（仅Unix/Linux/macOS） #

如果游戏运行在类Unix系统上，可借助信号机制实现更简洁的超时控制：

import signal

def timeout_handler(signum, frame):
    print('\nThe guards catch you. They execute you on the spot. You die.')
    exit()

def escape_scene():
    timeout = 5
    # 设置信号触发的超时逻辑
    signal.signal(signal.SIGALRM, timeout_handler)
    signal.alarm(timeout)
    
    decisions = ["left", "right", "up"]
    print("You walk into an opening filled with guards! Where do you go?")
    answer = ""
    while answer not in decisions:
        print("Options: left/right/up")
        try:
            answer = input()
            # 用户输入成功，取消信号定时器
            signal.alarm(0)
        except:
            pass
        
        if answer == "left":
            nothing()
        elif answer == "right":
            nothing()
        elif answer == "up":
            example()
        else:
            print("That is not an option.")
            # 递归前取消信号定时器
            signal.alarm(0)
            escape_scene()

# 替换为你的实际游戏逻辑函数
def nothing():
    print("You chose left/right, nothing happens.")

def example():
    print("You climbed up and escaped!")

escape_scene()

关键注意事项： #

• 用户输入成功后必须取消定时器/信号，避免后续误触发超时逻辑。
• 递归调用场景函数时，一定要先取消当前的定时器，否则会出现多个定时器同时运行的问题，导致错误触发超时。

内容的提问来源于stack exchange，提问作者Viul