根据对象的name属性移除数组中的非重复对象

要实现这个需求，我们可以分两步操作：先统计每个name属性的出现频次，再根据频次过滤数组，只保留出现多次的对象。

实现代码（JavaScript） #

// 原始数组
const originalArray = [
    { "name": "Storage Capacity", "value": "64GB" },
    { "name": "Manufacturer Color", "value": "Black / Red / White / Green / Purpule" },
    { "name": "Carrier", "value": "Unlocked" },
    { "name": "Carrier", "value": "AT&T" },
    { "name": "Brand", "value": "Apple" },
    { "name": "MPN", "value": "NA" },
    { "name": "Model", "value": "Iphone 11" },
    { "name": "Color", "value": "Black" },
    { "name": "Color", "value": "White" },
    { "name": "Storage Capacity", "value": "128GB" },
];

// 第一步：统计每个name的出现频次
const nameCount = originalArray.reduce((countObj, item) => {
    countObj[item.name] = (countObj[item.name] || 0) + 1;
    return countObj;
}, {});

// 第二步：过滤数组，仅保留出现次数>1的对象
const filteredArray = originalArray.filter(item => nameCount[item.name] > 1);

console.log(filteredArray);

输出结果 #

运行上述代码后，filteredArray将只包含name为Color、Storage Capacity、Carrier的对象，符合需求：

[
    { "name": "Storage Capacity", "value": "64GB" },
    { "name": "Carrier", "value": "Unlocked" },
    { "name": "Carrier", "value": "AT&T" },
    { "name": "Color", "value": "Black" },
    { "name": "Color", "value": "White" },
    { "name": "Storage Capacity", "value": "128GB" }
]

内容的提问来源于stack exchange，提问作者Gia Nebieridze