如何从返回数据中提取多个firstLanguage对象至单个变量

假设你拿到的批量返回数据是数组/列表形式（比如命名为responseData），里面包含多个你提供的结构对象，以下是几种主流编程语言的实现方式：

JavaScript实现 #

// 示例批量数据
const responseData = [
  {
    type: 'Text',
    firstLanguage: {
      translation: 'When the Constituent Assembly passed the Objective Resolution?',
      option_a: '14th February 1949',
      option_b: '12th March 1949',
      option_c: '9th June 1949',
      option_d: '15th August 1949',
      correct_answer: 4
    },
    secondLanguage: { /* ... */ }
  },
  // 更多同结构对象...
];

// 提取所有firstLanguage到变量中
const firstLanguageItems = responseData.map(item => item.firstLanguage);

Python实现 #

# 示例批量数据
response_data = [
    {
        'type': 'Text',
        'firstLanguage': {
            'translation': 'When the Constituent Assembly passed the Objective Resolution?',
            'option_a': '14th February 1949',
            'option_b': '12th March 1949',
            'option_c': '9th June 1949',
            'option_d': '15th August 1949',
            'correct_answer': 4
        },
        'secondLanguage': { ... }
    },
    # 更多同结构字典...
]

# 提取所有firstLanguage到变量中
first_language_items = [item['firstLanguage'] for item in response_data]

Java实现 #

import java.util.ArrayList;
import java.util.List;
import java.util.Map;

public class DataExtractor {
    public static void main(String[] args) {
        // 示例批量数据
        List<Map<String, Object>> responseData = new ArrayList<>();
        // 填充批量数据...

        // 提取所有firstLanguage到变量中
        List<Map<String, Object>> firstLanguageItems = new ArrayList<>();
        for (Map<String, Object> item : responseData) {
            firstLanguageItems.add((Map<String, Object>) item.get("firstLanguage"));
        }
    }
}

核心逻辑一致：遍历批量数据集合，逐个提取每个元素中的firstLanguage属性，将结果存入新的集合变量中。

内容的提问来源于stack exchange，提问作者user15421419