如何按EmployeeName升序排序按EmployeeId分组的数组？

现有一组按EmployeeId分组的员工数据，需要按EmployeeName进行升序排序，最终返回与输入格式一致的结构。

输入数据 #

{
  13: [{employeeId:13,employeeName:"Nova"}],
  21: [{employeeId:21,employeeName:"Avinash"},{employeeId:21,employeeName:"Avinash"}],
  23: [{employeeId:23,employeeName:"Mamatha"}],
  24: [{employeeId:24,employeeName:"Swetha"}]
}

解决方法 #

可以通过以下步骤实现排序：

• 将对象转换为键值对数组，方便进行排序操作
• 根据每个分组中员工的employeeName进行升序比较（因分组内员工名称一致，取每组第一个员工的名称即可）
• 将排序后的键值对数组重新转换为对象

具体代码实现如下：

const groupedData = {
  13: [{employeeId:13,employeeName:"Nova"}],
  21: [{employeeId:21,employeeName:"Avinash"},{employeeId:21,employeeName:"Avinash"}],
  23: [{employeeId:23,employeeName:"Mamatha"}],
  24: [{employeeId:24,employeeName:"Swetha"}]
};

// 转换为键值对数组并按EmployeeName升序排序
const sortedEntries = Object.entries(groupedData).sort((a, b) => {
  const nameA = a[1][0].employeeName.toLowerCase();
  const nameB = b[1][0].employeeName.toLowerCase();
  return nameA.localeCompare(nameB);
});

// 转回目标格式的对象
const sortedGroupedData = Object.fromEntries(sortedEntries);

console.log(sortedGroupedData);

预期输出 #

{
  21: [{employeeId:21,employeeName:"Avinash"},{employeeId:21,employeeName:"Avinash"}],
  23: [{employeeId:23,employeeName:"Mamatha"}],
  13: [{employeeId:13,employeeName:"Nova"}],
  24: [{employeeId:24,employeeName:"Swetha"}]
}

内容的提问来源于stack exchange，提问作者sra