JavaScript井字棋verifyVictory函数语法错误求助

你的代码存在两个关键语法问题，直接导致VS Code标记错误：

• 赋值/相等判断混淆：所有state.cX = state.cY的写法错误，=是赋值运算符，你需要的是判断相等的==，用=会意外修改state的值，同时逻辑判断完全失效。
• else if语法结构错误：else if必须把判断条件放在()内，你现在把条件写在了后续的{}里，不符合JavaScript语法规范。

修复后的完整代码：

const verifyVictory = () => {
    if(
        (state.c1 == state.c2 && state.c2 == state.c3 && state.c1 > 0) ||
        (state.c4 == state.c5 && state.c5 == state.c6 && state.c4 > 0) ||
        (state.c7 == state.c8 && state.c8 == state.c9 && state.c7 > 0) ||

        (state.c1 == state.c4 && state.c4 == state.c7 && state.c1 > 0) ||
        (state.c2 == state.c5 && state.c5 == state.c8 && state.c2 > 0) ||
        (state.c3 == state.c6 && state.c6 == state.c9 && state.c3 > 0) ||

        (state.c1 == state.c5 && state.c5 == state.c9 && state.c1 > 0) ||
        (state.c3 == state.c5 && state.c5 == state.c7 && state.c3 > 0) 
    ){
        return true;
    } else if (
        state.c1 != 0 &&
        state.c2 != 0 &&
        state.c3 != 0 &&
        state.c4 != 0 &&
        state.c5 != 0 &&
        state.c6 != 0 &&
        state.c7 != 0 &&
        state.c8 != 0 &&
        state.c9 != 0
    ) {
        return null;
    } else {
        return false;
    }
};

额外提示：如果要更严谨，可使用===严格相等判断（把==换成===，!=换成!==），避免类型转换带来的意外问题。

内容的提问来源于stack exchange，提问作者Kalem