Node.js readline模块异常：无法进入后续逻辑，控制台无响应

你代码里的核心问题是**rl.question()本身不返回Promise**，直接用await调用它会导致Promise永远处于pending状态，程序彻底卡住，所以控制台失去响应。

把rl.question()包装成返回Promise的函数，这样就能正常用async/await处理异步输入了。修改后的完整代码如下：

const readline = require('readline');
const rl = readline.createInterface({ input: process.stdin, output: process.stdout });

// 把question方法包装成Promise
function askQuestion(prompt) {
  return new Promise(resolve => {
    rl.question(prompt, resolve);
  });
}

async function clientOpener() {
  const startGame = await askQuestion(`Choose a number:
1)Start a bowling game
2)Exit simulation
`);
  
  const y = "1";
  const n = "2";
  
  if (y === startGame) {
    const playerCount = await askQuestion("Ok how many players will there be (MAX: 8 players)\n");
    const parsedInput = parseInt(playerCount);
    
    if (parsedInput > 0 && parsedInput <= 8) {
      let listOfNames = [];
      for (let i=0; i<parsedInput; i++) {
        const name = await askQuestion(`Enter name #${i}\n`);
        listOfNames.push(name);
        console.log(`Added ${name} to list of players\n`);
      }
      console.log(listOfNames);
    }
    rl.close();
  } else if (n === startGame) {
    console.log("Ending interface");
    rl.close();
  } else {
    console.log("Please enter a valid option");
    clientOpener();
  }
}

clientOpener();

• 新增askQuestion函数，将rl.question的回调逻辑转换为Promise，让await能正常等待用户输入
• 把clientOpener改为async函数，直接用await调用包装后的提问函数，避免嵌套回调和无效的await
• 统一处理提示信息的换行，保证输出格式清晰

内容的提问来源于stack exchange，提问作者macman926