如何使用apply函数将htest列表中的conf.int值乘以100?
Solution
To multiply the conf.int values in each htest object within your list by 100, you can use lapply() to iterate over the list and modify each object while preserving its original structure and attributes.
Step-by-Step Code
# Example data x <- list(structure(list(conf.int = structure(c(0.054, 0.57), conf.level = 0.95)), class = "htest"), structure(list( conf.int = structure(c(0.01638, 0.4003372 ), conf.level = 0.95)), class = "htest")) # Scale conf.int values by 100 x_modified <- lapply(x, function(obj) { obj$conf.int <- obj$conf.int * 100 obj }) # View the modified result x_modified
Output
[[1]] 95 percent confidence interval: 5.4 57.0 [[2]] 95 percent confidence interval: 1.63800 40.03372
This method keeps the conf.level attribute of each conf.int vector intact, ensuring the htest objects maintain their metadata while the confidence interval values are scaled as requested.
内容的提问来源于stack exchange,提问作者D. Shin
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