能否在同一条SQL查询中同时使用LIKE和MATCH AGAINST？

• 语法错误修正：你的SQL语句里OR后面多写了一个WHERE，SQL语法要求WHERE子句只能有一个开头，多个条件直接用OR/AND连接即可。修正后的基础SQL如下：

SELECT * FROM posts WHERE title LIKE '%$search%' OR MATCH (title) AGAINST('$search' IN NATURAL LANGUAGE MODE)

• 必须修复的SQL注入风险：直接把用户输入的$search拼进SQL语句里，属于高危写法，极易遭遇SQL注入攻击。建议用PDO预处理语句替代，示例代码：

$search = "user search";
$stmt = $connection->prepare("SELECT * FROM posts WHERE title LIKE ? OR MATCH (title) AGAINST(? IN NATURAL LANGUAGE MODE)");
$likeKeyword = "%{$search}%";
$stmt->execute([$likeKeyword, $search]);
$data = $stmt->fetchAll();

• 实现你的需求逻辑：如果要区分短词用LIKE、长词/多词用MATCH AGAINST，可以先判断搜索词的状态，再选择对应查询逻辑，不用强行OR两个条件：

$search = trim("user search");
$wordCount = count(explode(' ', $search));
// 自定义判断规则：比如词数>1 或 单词语长>5时用全文搜索
if ($wordCount > 1 || strlen($search) > 5) {
    $stmt = $connection->prepare("SELECT * FROM posts WHERE MATCH (title) AGAINST(? IN NATURAL LANGUAGE MODE)");
    $stmt->execute([$search]);
} else {
    $stmt = $connection->prepare("SELECT * FROM posts WHERE title LIKE ?");
    $stmt->execute(["%{$search}%"]);
}
$data = $stmt->fetchAll();

内容的提问来源于stack exchange，提问作者Table