如何在Python字典中实现地区人口与儿童数量的增量更新？

核心修改点 #

• 将输入的增量转换为整数类型，避免运算错误
• 更新city字典中对应地区的人口和儿童数量
• 可选：将更新后的数据写回area.txt，保证数据持久化

修改后的完整代码 #

area="""AREA,POPULATION,CHILD
ARKANSAS,2000,20
TEXAS,50,5"""
def createFiles():
    x = open('area.txt','w')
    x.write(area)
    x.close()
createFiles()


city = {}
total = 0
with open('area.txt', 'r') as file:
    next(file)
    for line in file:
        data = line.strip().split(',')
        place = data[0]
        city[place] = {}
        city[place]['Population'] = int(data[1])
        city[place]['Children'] = int(data[2])
print(city)
choose=input('Choose area ARKANSAS/TEXAS: ')
addPopu=int(input('Add population: '))
addChild=int(input('Add Children: '))

# 更新字典中对应地区的数据
city[choose]['Population'] += addPopu
city[choose]['Children'] += addChild

# 打印更新后的结果
print(city)

# 可选：将更新后的数据同步写入area.txt文件
with open('area.txt', 'w') as file:
    file.write("AREA,POPULATION,CHILD\n")
    for area_name, info in city.items():
        line = f"{area_name},{info['Population']},{info['Children']}\n"
        file.write(line)

代码说明 #

1. 输入类型转换：把用户输入的增量从字符串转为整数，确保能正常执行加法运算
2. 字典数据更新：通过用户选择的地区名称，直接定位到字典中对应条目，完成数值累加
3. 结果输出：打印更新后的city字典，与预期输出一致
4. 文件同步（可选）：如果需要让本地文件的内容也保持最新，将字典数据重新整理为CSV格式写入area.txt，下次读取时会直接加载更新后的数据

运行示例输出 #

{'ARKANSAS': {'Population': 2000, 'Children': 20}, 'TEXAS': {'Population': 50, 'Children': 5}}
Choose area ARKANSAS/TEXAS: TEXAS
Add population: 10
Add Children: 5
{'ARKANSAS': {'Population': 2000, 'Children': 20}, 'TEXAS': {'Population': 60, 'Children': 10}}

内容的提问来源于stack exchange，提问作者Griffin De Leon